Whats the distance between -7 and -1 on a number line.

Angle FEDwith angleF=90degree, ED=36, and FE=22, calcularé the measures of the unknown angles and the unknown side length of the

Flauer [41]

Answer:

$\angle D=37.7^{\circ}$

$\angle E=52.3^{\circ}$

$FD\approx 28.5$

Step-by-step explanation:

Please find the attachment.

We have been given that angle FED with angle F=90 degree, ED=36, and FE=22. We are asked to find the unknown angles and the unknown side length of the triangle.

We will use sine to solve for angle D as:

$\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}$

$\text{sin}(D)=\frac{22}{36}$

$D=\text{sin}^{-1}(\frac{22}{36})$

$D=37.66988696^{\circ}$

$D\approx 37.7^{\circ}$

Therefore, measure of angle D is 37.7 degrees.

Now, we will find measure of angle E using angle sum property.

$m\angle E+m\angle F+m\angle D=180^{\circ}$

$m\angle E+90^{\circ}+37.7^{\circ}=180^{\circ}$

$m\angle E+127.7^{\circ}=180^{\circ}$

$m\angle E+127.7^{\circ}-127.7^{\circ}=180^{\circ}-127.7^{\circ}$

$m\angle E=52.3^{\circ}$

Therefore, measure of angle E is 52.3 degrees.

We will use Pythagoras theorem to solve for side FD as:

$FD^2+EF^2=ED^2$

$FD^2+22^2=36^2$

$FD^2+484=1296$

$FD^2=1296-484$

$FD^2=812$

$FD=\sqrt{812}$

$FD=28.495613697\\\\FD\approx 28.5$

Therefore, length of side FD is approximately 28.5 units.

6 0

3 years ago

36) The speed of a boat in still water is 5km/hr. If the speed of the boat against the stream is 3

Radda [10]

Answer:

2km/hr

Step-by-step explanation:

Given the following

Speed of boat in water = 5km/hr

Speed of boat against stream = 3km/hr

Since the speed of boat is going against that of the stream, hence, the speed of the stream will be the difference between the speed of boat and that when the boat is against the stream

Speed of stream = 5km/hr - 3km/hr

Speed of stream = 2km/hr

hence the required speed of stream is 2km/hr

5 0

3 years ago

X+2>7 write the solution set in interval notation

REY [17]

Answer:

(5, infinitysymbol)

Step-by-step explanation:

First solve the inequality. Subtract 2 from both sides.

x + 2 > 7

x > 5

So that is one way of writing the answer and it is hopefully kind of understandable. X>5 means all the numbers greater (bigger) than 5, forever to infinity.

Interval notation is a way of writing a set or group of numbers. Interval notation uses ( ) parenthesis or [ ] square brackets. Then two numbers go inside with a comma in between. The first number is where the set of numbers start and the second number is where the set ends. You always put parenthesis around the infinity symbol or negative infinity symbol. You only use a square bracket if the inequality symbols have the "or equal to" underline under the > or <.

So x > 5 in interval notation is:

(5, infinitysymbol)

This shows that 5 is not included in the solution; and all the numbers forever bigger than five are solutions as well.

5 0

2 years ago

How can u regroup the number 24

mars1129 [50]

You could have 6 groups of four, or 2 groups of 12, or 4 groups of 6 or 12 groups of 2 or 3 groups of 8 or 8 groups of 3

5 0

3 years ago

Six checkers are placed in three boxes: two red are in a box labeled "RR"; two black are in a box labelled "BB"; a red and a bla

Nezavi [6.7K]

Answe and Step-by-step explanation:

Looking at the question the way it was asked, it is easy because it said they have been labelled, so you don't have to stress yourself. Although, if what is intended is, the labelling got wrong along the way and how do you identify the correct one? Then this is what to do:

Go to the one labelled RB. Since I'm assuming that the labelling got wrong, if you pick a red, it means what we have should be a RR and if we picked a black, it means what we have is a BB and we can't have a RB because it was labelled wrongly.

Let's assume he saw a red,

We know that the BB box was labelled wrongly, and we already determined that the box with RB is a RR. Therefore, the box BB can never be RR(because we've seen it already) and it's certainly not BB (due to the fact that they were labelled wrongly). So we have only one option left which is it being RB and whatever we have left will be BB.

If we assume what was picked from the wrongly labelled RB is black.

We know that the RR box was labelled wrongly, and we already determined that the box with RB is a BB. Therefore, the box RR can never be BB and it's certainly not RR (due to the fact that they were labelled wrongly). So we have only one option left which is it being RB and whatever we have left will be RR.

3 0

3 years ago