You are going to die most likely from being electrocuted
Answer:
<u>Eo = A/[-nB/A]^(1/n-1) + B/[-nB/A]^(n/n-1)</u>
Explanation:
<u>Step 1.</u>
Taking derivative of the equation with respect to 'r' we get:
d/dr(EN) = - A/r² - nB/r^(n+1)
Setting this equation to zero:
<u>Step 2.</u>
Solving for r:
- A/r² - nB/r^(n+1) = 0
A/r² + nB/r^(n+1) = 0
Ar^(n+1) + nBr² = 0
Ar^(n+1) = - nBr²
[r^(n+1)]/r² = - nB/A
r^(n+1-2) = - nB/A
r^(n-1) = - nB/A
Taking power 1/(n-1) on both sides:
r = [-nB/A]^(1/n-1)
This is the value of ro:
ro = [-nB/A]^(1/n-1)
<u>Step 3.</u>
Substituting value of ro in eqn we get value of Eo
<u>Eo = A/[-nB/A]^(1/n-1) + B/[-nB/A]^(n/n-1)</u>
Answer:
807.5N
Explanation:
The combined mass (m) on the back muscle is 55kg + 30kg = 85kg
Acceleration due to gravity (g) = 9.8m/s²
Therefore the force FB = ma = 85*9.8
FB= 807.5N
Answer:
Explanation:
The cylinder head sits on the engine and closes off the combustion chamber. The gap that remains between the cylinder head and the engine is completed by the head gasket. Another task of the cylinder head is to ensure the constant lubrication of the cylinder
The pressure of water is 7.3851 kPa
<u>Explanation:</u>
Given data,
V = 150×
![m^{3}](https://tex.z-dn.net/?f=m%5E%7B3%7D)
m = 1 Kg
= 2 MPa
= 40°C
The waters specific volume is calculated:
= V/m
Here, the waters specific volume at initial condition is
, the containers volume is V, waters mass is m.
= 150×
/1
= 0.15
/ Kg
The temperature from super heated water tables used in interpolation method between the lower and upper limit for the specific volume corresponds 0.15
/ Kg and 0.13
/ Kg.
= 350+(400-350) ![\frac{0.15-0.13}{0.1522-0.1386}](https://tex.z-dn.net/?f=%5Cfrac%7B0.15-0.13%7D%7B0.1522-0.1386%7D)
= 395.17°C
Hence, the initial temperature is 395.17°C.
The volume is constant in the rigid container.
=
= 0.15
/ Kg
In saturated water labels for
= 40°C.
= 0.001008
/ Kg
= 19.515
/ Kg
The final state is two phase region
<
<
.
In saturated water labels for
= 40°C.
=
= 7.3851 kPa
= 7.3851 kPa