Answer:
Explanation:
Enforcing OSHA, Occupational Safety and Health Administration, standards is not a job for electricians, lawmakers or tax collectors. The right answer is safety inspectors.
Answer:
Wind energy is converted to Mechanical energy which is then converted in to electrical energy
Explanation:
In a wind mill the following energy conversions take place
a) Wind energy is converted into Mechanical energy (rotation of rotor blades)
b) Mechanical energy is converted into electrical energy (by using electric motor)
This electrical energy is then used for transmission through electric lines.
Answer:
a)
, b)
,
,
, c)
,
,
, ![\Delta t_{mean} = \frac{1 + \sqrt{2} }{6000}\,h](https://tex.z-dn.net/?f=%5CDelta%20t_%7Bmean%7D%20%3D%20%5Cfrac%7B1%20%2B%20%5Csqrt%7B2%7D%20%7D%7B6000%7D%5C%2Ch)
Explanation:
a) The total number of users that can be accomodated in the system is:
![n = \frac{10\,km^{2}}{1\,\frac{km^{2}}{cell} }\cdot (100\,\frac{users}{cell} )](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B10%5C%2Ckm%5E%7B2%7D%7D%7B1%5C%2C%5Cfrac%7Bkm%5E%7B2%7D%7D%7Bcell%7D%20%7D%5Ccdot%20%28100%5C%2C%5Cfrac%7Busers%7D%7Bcell%7D%20%29)
![n = 1000\,users](https://tex.z-dn.net/?f=n%20%3D%201000%5C%2Cusers)
b) The length of the side of each cell is:
![l = \sqrt{1\,km^{2}}](https://tex.z-dn.net/?f=l%20%3D%20%5Csqrt%7B1%5C%2Ckm%5E%7B2%7D%7D)
![l = 1\,km](https://tex.z-dn.net/?f=l%20%3D%201%5C%2Ckm)
Minimum time for traversing a cell is:
![\Delta t_{min} = \frac{l}{v}](https://tex.z-dn.net/?f=%5CDelta%20t_%7Bmin%7D%20%3D%20%5Cfrac%7Bl%7D%7Bv%7D)
![\Delta t_{min} = \frac{1\,km}{30\,\frac{km}{h} }](https://tex.z-dn.net/?f=%5CDelta%20t_%7Bmin%7D%20%3D%20%5Cfrac%7B1%5C%2Ckm%7D%7B30%5C%2C%5Cfrac%7Bkm%7D%7Bh%7D%20%7D)
![\Delta t_{min} = \frac{1}{30}\,h](https://tex.z-dn.net/?f=%5CDelta%20t_%7Bmin%7D%20%3D%20%5Cfrac%7B1%7D%7B30%7D%5C%2Ch)
The maximum time for traversing a cell is:
![\Delta t_{max} = \frac{\sqrt{2}\cdot l }{v}](https://tex.z-dn.net/?f=%5CDelta%20t_%7Bmax%7D%20%3D%20%5Cfrac%7B%5Csqrt%7B2%7D%5Ccdot%20l%20%7D%7Bv%7D)
![\Delta t_{max} = \frac{\sqrt{2} }{30}\,h](https://tex.z-dn.net/?f=%5CDelta%20t_%7Bmax%7D%20%3D%20%5Cfrac%7B%5Csqrt%7B2%7D%20%7D%7B30%7D%5C%2Ch)
The approximate time is giving by the average of minimum and maximum times:
![\Delta t_{mean} = \frac{1+\sqrt{2} }{2}\cdot\frac{l}{v}](https://tex.z-dn.net/?f=%5CDelta%20t_%7Bmean%7D%20%3D%20%5Cfrac%7B1%2B%5Csqrt%7B2%7D%20%7D%7B2%7D%5Ccdot%5Cfrac%7Bl%7D%7Bv%7D)
![\Delta t_{mean} = \frac{1 + \sqrt{2} }{60}\,h](https://tex.z-dn.net/?f=%5CDelta%20t_%7Bmean%7D%20%3D%20%5Cfrac%7B1%20%2B%20%5Csqrt%7B2%7D%20%7D%7B60%7D%5C%2Ch)
c) The total number of users that can be accomodated in the system is:
![n = \frac{10\times 10^{6}\,m^{2}}{100\,m^{2}}\cdot (100\,\frac{users}{cell} )](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B10%5Ctimes%2010%5E%7B6%7D%5C%2Cm%5E%7B2%7D%7D%7B100%5C%2Cm%5E%7B2%7D%7D%5Ccdot%20%28100%5C%2C%5Cfrac%7Busers%7D%7Bcell%7D%20%29)
![n = 10000000\,users](https://tex.z-dn.net/?f=n%20%3D%2010000000%5C%2Cusers)
The length of each side of the cell is:
![l = \sqrt{100\,m^{2}}](https://tex.z-dn.net/?f=l%20%3D%20%5Csqrt%7B100%5C%2Cm%5E%7B2%7D%7D)
![l = 10\,m](https://tex.z-dn.net/?f=l%20%3D%2010%5C%2Cm)
Minimum time for traversing a cell is:
![\Delta t_{min} = \frac{l}{v}](https://tex.z-dn.net/?f=%5CDelta%20t_%7Bmin%7D%20%3D%20%5Cfrac%7Bl%7D%7Bv%7D)
![\Delta t_{min} = \frac{0.01\,km}{30\,\frac{km}{h} }](https://tex.z-dn.net/?f=%5CDelta%20t_%7Bmin%7D%20%3D%20%5Cfrac%7B0.01%5C%2Ckm%7D%7B30%5C%2C%5Cfrac%7Bkm%7D%7Bh%7D%20%7D)
![\Delta t_{min} = \frac{1}{3000}\,h](https://tex.z-dn.net/?f=%5CDelta%20t_%7Bmin%7D%20%3D%20%5Cfrac%7B1%7D%7B3000%7D%5C%2Ch)
The maximum time for traversing a cell is:
![\Delta t_{max} = \frac{\sqrt{2}\cdot l }{v}](https://tex.z-dn.net/?f=%5CDelta%20t_%7Bmax%7D%20%3D%20%5Cfrac%7B%5Csqrt%7B2%7D%5Ccdot%20l%20%7D%7Bv%7D)
![\Delta t_{max} = \frac{\sqrt{2} }{3000}\,h](https://tex.z-dn.net/?f=%5CDelta%20t_%7Bmax%7D%20%3D%20%5Cfrac%7B%5Csqrt%7B2%7D%20%7D%7B3000%7D%5C%2Ch)
The approximate time is giving by the average of minimum and maximum times:
![\Delta t_{mean} = \frac{1+\sqrt{2} }{2}\cdot\frac{l}{v}](https://tex.z-dn.net/?f=%5CDelta%20t_%7Bmean%7D%20%3D%20%5Cfrac%7B1%2B%5Csqrt%7B2%7D%20%7D%7B2%7D%5Ccdot%5Cfrac%7Bl%7D%7Bv%7D)
![\Delta t_{mean} = \frac{1 + \sqrt{2} }{6000}\,h](https://tex.z-dn.net/?f=%5CDelta%20t_%7Bmean%7D%20%3D%20%5Cfrac%7B1%20%2B%20%5Csqrt%7B2%7D%20%7D%7B6000%7D%5C%2Ch)
Complying with DSEAR involves:
Assessing risks. ...
Preventing or controlling risks. ...
Control measures. ...
Mitigation. ...
Preparing emergency plans and procedures. ...
Providing information, instruction and training for employees. ...
Places where explosive atmospheres may occur ('ATEX' requirements)
hse uk
Answer:
Machine 2 has a higher process capability index, it would be best considered for purchase.
Explanation:
Process capability index: Cpk= Min [(mean-L spec)/3sd; (U spec-mean)/3sd]
For machine 1, mean= 48mm and L spec= 46 and U spec= 50, Standard deviation sd= 0.7
Cpk= [0.952;0.952]= 0.952
For machine 2, mean= 47 and L spec= 46 and U spec= 50, Standard deviation sd= 0.3
Cpk= [1.111;3.333]= 1.111
It is clearly observed from the calculations above that the Cpk value of machine 2 is higher than that of machine 1.
Since machine 2 has a higher process capability index, it would be best considered for purchase.