Answer:
%Program prompts user to input vector
v = input('Enter the input vector: ');
%Program shows the value that user entered
fprintf('The input vector:\n ')
disp(v)
%Loop for checking all array elements
for i = 1 : length(v)
%check if the element is a positive number
if v(i) > 0
%double the element
v(i) = v(i) * 2;
%else the element is negative number.
else
%triple the element
v(i) = v(i) * 3;
end
end
%display the modified vector
fprintf('The modified vector:\n ')
disp(v)
Answer:
moment of inertia = 4.662 * 10^6 
Explanation:
Given data :
Mass of machine = 400 kg = 400 * 9.81 = 3924 N
length of span = 3.2 m
E = 200 * 10^9 N/m^2
frequency = 9.3 Hz
Wm ( angular frequency ) = 2 
= 58.434 rad/secs
also Wm = 
------- EQUATION 1
g = 9.81
deflection of simply supported beam
t = 
insert the value of t into equation 1
W
= 
make I the subject of the equation
I ( Moment of inertia about the neutral axis ) = 
I = 
= 4.662 * 10^6
I think because if you’ve already turned it in they might as well grade asap instead of waiting
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Answer:
C
Explanation:
I just did the test on enginuity and it also is the only one that makes sence
