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PSYCHO15rus [73]

2 years ago

13

Angela uses 2/3 cup of strawberries to make 5/6 liter of smoothie what is the unit rate in cups of strawberries per liter of smo

othie

1 answer:

pogonyaev2 years ago

5 0

Answer:

14/65

Step-by-step explanation:

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A car travels 15 miles in 15 minutes how many miles does it travel in 2 hours

zubka84 [21]

Answer:

120 miles in 2 hour

Step-by-step explanation:

One hour has 4 times 15 minutes, so you need to do 15 miles x 4 and that time 2 because its 2 hours.

5 0

2 years ago

laurie uses 0.25 pounds of butter to make a batch of her grandmother's cookies. She needs to make 4.5 times ther ecipe for the s

Gnesinka [82]

Laurie must make 4.5 batches for the school bake sale, and 2 batches for her family. Therefore, in total, Laurie must make 4.5 + 2 = 6.5 batches of cookies.

Since each batch of cookies requires 0.25 pounds of butter, we can multiply that amount by the number of batches baked: 0.25 * 6.5 = 1.625 pounds of butter.

So Laurie uses 1.625 pounds of butter to make all the cookies.

6 0

3 years ago

When you convert 100ft per second to inches per second will there be more or less than 100 inches

Firlakuza [10]

It would be more than 100 inches because in one foot is 12 inches, so take 100 x 12 = 1200 inches

3 0

3 years ago

A new dental bondlng agent. When bonding teeth, orthodontists must maintain a dry field. A new bonding adhesive(called "Smartbon

Gemiola [76]

Answer:

(a) <em>H</em>₀: <em>μ ≥ 5.70 </em><em>vs. </em><em>Hₐ</em>:<em>μ < 5.70</em>

(b) The rejection region is (<em>t₀.₀₁,₉</em> <em>≤ -2.821</em>).

(c) The value of the test statistic is -4.33.

(d) The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

Step-by-step explanation:

A hypothesis test should be conducted to determine that the if the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

(a)

The hypothesis is:

<em>H</em>₀: The true mean breaking strength of the new bonding adhesive is not less than 5.70 Mpa, i.e. <em>μ ≥ 5.70</em><em>.</em>

<em>Hₐ</em>: The true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa, i.e. <em>μ < 5.70</em><em>.</em>

(b)

The alternate hypothesis indicates that the hypothesis test is left-tailed.

The rejection region for the left tailed test will be towards the lower tail of the t<em>-</em>distribution curve.

The significance level of the test is: <em>α</em> = 0.01.

The critical value is:

$t_{\alpha ,(n-1)}=t_{0.01,(10-1)}=t_{0.01,9}$

Use the <em>t-</em>table for the critical value.

$t_{\alpha ,(n-1)}=t_{0.01,9}=-2.821$

Since rejection region is in the lower tail the critical value will be negative.

Thus, the rejection region is (<em>t₀.₀₁,₉</em> <em>≤ -2.821</em>).

(c)

The test statistic value is:

$t=\frac{\bar x-\mu}{s/\sqrt{n}}$

Given:

$\bar x=5.07\\s=0.46\\n=10\\\mu=5.70$

Compute the value of the <em>t</em>-statistic as follows:

$t=\frac{\bar x-\mu}{s/\sqrt{n}}=\frac{5.07-5.70}{0.46/\sqrt{10}} =-4.33$

The value of the test statistic is -4.33.

(d)

The value of the test is less than the critical value.

$t=-4.33$

This implies that the test statistic lies in the rejection region.

Hence the null hypothesis will be rejected at 1% significance level.

<u>Conclusion:</u>

As the null hypothesis is rejected it can be concluded that the true mean breaking strength of the new bonding adhesive is less than 5.70 Mpa.

(e)

The conditions required for the <em>t-</em>test for single mean to be valid is:

The data should be continuous.
The parent population should be normally distributed.
The sample should be randomly selected.

5 0

3 years ago

oy is training for a triathlon. She runs a distance of 2x miles, cycles a distance of (x2 + 7) miles, and swims a distance of (x

Evgesh-ka [11]

Add
2x+x²+7+x-2
x²+3x+5 is the distance

7 0

3 years ago