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larisa [96]
3 years ago
8

The ordered-pairs. y= 2x

Mathematics
2 answers:
Naya [18.7K]3 years ago
8 0

Answer:

i think its (0,0) ,(1,2)

Step-by-step explanation:

pls pls pls dont report me if wrong

Angelina_Jolie [31]3 years ago
6 0

Answer:

(-1, -2) (0,0) (1,2) (2,4) (3, 6) (4, 8)

Step-by-step explanation:

I fixed it lol. The points are:

(-1, -2) (0,0), (1,2), (2,4) (3, 6) (4, 8)

I hope I helped ^^

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EASY MIDDLE SCHOOL MATH!!!
elena-14-01-66 [18.8K]

Answer:

18 boys

Step-by-step explanation:

18=6x3

6x4=24

24+18=42

8 0
3 years ago
Count twenty of fifty equal parts
kondaur [170]

Answer:

I think 20/50 is the answer you're looking.

5 0
4 years ago
Read 2 more answers
Construct a confidence interval of the population proportion at the given level of confidence. x = 125, n = 250, 90 % confidence
madam [21]

Answer: 90% confidence interval would be (0.448, 0.552).

Step-by-step explanation:

Since we have given that

x = 125

n = 250

So, \hat{p}=\dfrac{x}{n}=\dfrac{125}{250}=0.5

We need to find the 90% confidence interval.

so, z = 1.64

So, interval would be

\hat{p}\pm z\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.5\pm 1.64\sqrt{\dfrac{0.5\times 0.5}{250}}\\\\=0.5\pm 0.0519\\\\=(0.5-0.0519,0.5+0.0519)\\\\=(0.448,0.552)

Hence, 90% confidence interval would be (0.448, 0.552)

3 0
4 years ago
Which expression is equivalent to one over fourn − 16?
ryzh [129]
The correct answer is 1/4(n - 64).

1/4n - 16  Write Original expression
0.25n -16     Simplify the fraction
0.25(n - 64)      Distribute(take out) 0.25 from n-16
1/4(n - 64)      Final Answer


I hope this helps!
8 0
3 years ago
How do you do this question?
madam [21]

Answer:

20

Step-by-step explanation:

A left Riemann sum approximates a definite integral as:

\int\limits^b_a {f(x)} \, dx \approx \sum\limits_{k=1}^{n}f(x_{k}) \Delta x \\where\ \Delta x = \frac{b-a}{n} \ and\ x_{k}=a+\Delta x \times (k-1)

Here, the integral is ∫₀² 9ˣ dx, and the number of subintervals is n = 4.

So Δx = 2/n = 1/2, and x = 2(k−1)/n = (k−1)/2.

Plugging in:

∑₁⁴ 9^((k−1)/2) (1/2)

1/2 ∑₁⁴ 9^((k−1)/2)

1/2 (9^((1−1)/2) + 9^((2−1)/2) + 9^((3−1)/2) + 9^((4−1)/2))

1/2 (9^(0) + 9^(1/2) + 9^(1) + 9^(3/2))

1/2 (1 + 3 + 9 + 27)

20

8 0
3 years ago
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