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VMariaS [17]
3 years ago
7

Combine the like terms to create an equivalent expression: −4y−4+(−3) PLZ SOMEONE HELP

Mathematics
1 answer:
tester [92]3 years ago
8 0

Answer:

-4y-7 i think

Step-by-step explanation:

sorry if im wrong but im pretty sure you combine -4 and -3, and -4 plus -3 is just -4 -3 so -7

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What is the coefficient of the third term in the binomial expansion of (a + b)6? 1 15 20 90
Sholpan [36]

Answer:  15

Step-by-step explanation:

(r+1)th term of (a+b)^n is given by:-

T_{r+1}=\ ^nC_r(a)^{n-r}b^r

For (a+b)^6 , n= 6

T_3=T_{2+1}=\ ^6C_2(a)^{6-2}(b)^2\\\\

=\ \dfrac{6!}{4!2!}a^4b^2\ \ \ [^nC_r=\dfrac{n!}{r!(n-r)!}]\\\\=\dfrac{6\times5\times4!}{4!\times2}a^4b^2\\\\=3\times5a^4b^2\\\\ =15a^4b^2

Hence, the coefficient of the third term in the binomial expansion of  (a+b)^6 is 15.

3 0
3 years ago
Read 2 more answers
Tell whether the equation has one, zero, or infinitely many solutions.<br>2(x-1/2)=8+2x​
docker41 [41]

Answer: none

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Question 2 options:
Vikki [24]

Answer:

slope

point-slope form

correlation

Step-by-step explanation:

If you have a line and you know the coordinates of a point on the line, (x1, y1); and you know the  <u>slope</u>, m, you can write the equation of the line in  <u>point-slope form</u>, y - y1 = m(x - x1). 2 variable data whose point pattern can be represented best by a line is said to have a linear  <u>correlation</u>.

The slope, meaning how steep a line is, is represented by the variable m for linear equations.

y - y1 = m(x - x1) is point-slope form, one type of linear equation to represent a straight line. (There is also standard form and slope-intercept form).

Correlation is the relationship between things, like 2 variable data.

8 0
3 years ago
Solve the inequality t/4 &gt;7<br> And 2c/3 +1&gt;7
Maru [420]

Answer:   c > 12

Step-by-step explanation:tep  1  :

           c

Simplify   —

           3

Equation at the end of step  1  :

       c            

 ((2 • —) -  1) -  7  > 0  

       3            

Step  2  :

Rewriting the whole as an Equivalent Fraction :

2.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  3  as the denominator :

        1     1 • 3

   1 =  —  =  —————

        1       3  

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

2.2       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

2c - (3)     2c - 3

————————  =  ——————

   3           3    

Equation at the end of step  2  :

 (2c - 3)    

 ———————— -  7  > 0  

    3        

Step  3  :

Rewriting the whole as an Equivalent Fraction :

3.1   Subtracting a whole from a fraction

Rewrite the whole as a fraction using  3  as the denominator :

        7     7 • 3

   7 =  —  =  —————

        1       3  

Adding fractions that have a common denominator :

3.2       Adding up the two equivalent fractions

(2c-3) - (7 • 3)     2c - 24

————————————————  =  ———————

       3                3    

Step  4  :

Pulling out like terms :

4.1     Pull out like factors :

  2c - 24  =   2 • (c - 12)  

Equation at the end of step  4  :

 2 • (c - 12)

 ————————————  > 0  

      3      

Step  5  :

5.1    Multiply both sides by  3  

5.2    Divide both sides by  2  

Solve Basic Inequality :

5.3      Add  12  to both sides

            c > 12

Inequality Plot :

5.4      Inequality plot for

        0.667 X  - 8.000  >  0

 

 

One solution was found :

                  c > 12

3 0
3 years ago
Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that
kherson [118]

Answer:

The answer is

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

Step-by-step explanation:

Remember that Taylor says that

f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }

For this case

f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

5 0
3 years ago
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