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3 years ago

Maya has 5/6 cup of ice cream. how many 1/4 cup servings are in 5/6 cup of ice cream

1 answer:

6 0

Find the LCD (least common denominator)
$\frac{5}{6} and \frac{1}{4}$

it would be 12 (6x2=12 and 4x3=12)

so you multiply $\frac{5}{6}$ by 2 and get $\frac{10}{12}$
then multiply $\frac{1}{4}$ by 3 and get $\frac{3}{12}$

you get 3 WHOLE servings from $\frac{5}{6}$ cups of icecream

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For the given function, find the vertical and horizontal asymptote(s) (if there are any).

Doss [256]

There are three rules of finding the horizontal asymptote depending on the orders of the numerator and denominator. If the degrees are equal for the numerator and the denominator, then the horizontal asymptote is equal to y = the ratio of the coefficients of the highest order from the numerator and the denominator. If the degree in the numerator is less than the degree in the denominator, then there the x axis is the horizontal asymptote. If on the other hand, the order in the numerator is greater than that of the denominator, then there is no horizontal asymptote.

8 0

3 years ago

Part A

masya89 [10]

Answer:

Part A) The area of triangle i is $3\ cm^{2}$

Part B) The total area of triangles i and ii is $6\ cm^{2}$

Part C) The area of rectangle i is $20\ cm^{2}$

Part D) The area of rectangle ii is $32\ cm^{2}$

Part E) The total area of rectangles i and iii is $40\ cm^{2}$

Part F) The total area of all the rectangles is $72\ cm^{2}$

Part G) To find the surface area of the prism, we need to know only the area of triangle i and the area of rectangle i and the area of rectangle ii, because the area of triangle ii is equal to the area of triangle i and the area of rectangle iii is equal to the area of rectangle i

Part H) The surface area of the prism is $78\ cm^{2}$

Part I) The statement is false

Part J) The statement is true

Step-by-step explanation:

Part A) What is the area of triangle i?

we know that

The area of a triangle is equal to

$A=\frac{1}{2} (b)(h)$

we have

$b=4\ cm$

$h=1.5\ cm$

substitute

$A=\frac{1}{2} (4)(1.5)$

$Ai=3\ cm^{2}$

Part B) Triangles i and ii are congruent (of the same size and shape). What is the total area of triangles i and ii?

we know that

If Triangles i and ii are congruent

then

Their areas are equal

$Aii=Ai$

The area of triangle ii is equal to

$Aii=3\ cm^{2}$

The total area of triangles i and ii is equal to

$A=Ai+Aii$

substitute the values

$A=3+3=6\ cm^{2}$

Part C) What is the area of rectangle i?

we know that

The area of a rectangle is equal to

$A=(b)(h)$

we have

$b=2.5\ cm$

$h=8\ cm$

substitute

$Ai=(2.5)(8)$

$Ai=20\ cm^{2}$

Part D) What is the area of rectangle ii?

we know that

The area of a rectangle is equal to

$A=(b)(h)$

we have

$b=4\ cm$

$h=8\ cm$

substitute

$Aii=(4)(8)$

$Aii=32\ cm^{2}$

Part E) Rectangles i and iii have the same size and shape. What is the total area of rectangles i and iii?

we know that

Rectangles i and iii are congruent (have the same size and shape)

If rectangles i and iii are congruent

then

Their areas are equal

$Aiii=Ai$

The area of rectangle iii is equal to

$Aiii=20\ cm^{2}$

The total area of rectangles i and iii is equal to

$A=Ai+Aiii$

substitute the values

$A=20+20=40\ cm^{2}$

Part F) What is the total area of all the rectangles?

we know that

The total area of all the rectangles is

$At=Ai+Aii+Aiii$

substitute the values

$At=20+32+20=72\ cm^{2}$

Part G) What areas do you need to know to find the surface area of the prism?

To find the surface area of the prism, we need to know only the area of triangle i and the area of rectangle i and the area of rectangle ii, because the area of triangle ii is equal to the area of triangle i and the area of rectangle iii is equal to the area of rectangle i

Part H) What is the surface area of the prism? Show your calculation

we know that

The surface area of the prism is equal to the area of all the faces of the prism

The surface area of the prism is two times the area of triangle i plus two times the area of rectangle i plus the area of rectangle ii

$SA=2(3)+2(20)+32=78\ cm^{2}$

Part I) Read this statement: “If you multiply the area of one rectangle in the figure by 3, you’ll get the total area of the rectangles.” Is this statement true or false? Why?

The statement is false

Because, the three rectangles are not congruent

The total area of the rectangles is $72\ cm^{2}$ and if you multiply the area of one rectangle by 3 you will get $20*3=60\ cm^{2}$

$72\ cm^{2}\neq 60\ cm^{2}$

Part J) Read this statement: “If you multiply the area of one triangle in the figure by 2, you’ll get the total area of the triangles.” Is this statement true or false? Why?

The statement is true

Because, the triangles are congruent

8 0

3 years ago

One number is 8 a first number . A third number is 100 more than the first number . If the sum of three numbers is 750, find the

zloy xaker [14]

x+(x+8)+(x+100)=750
3x+108=750
3x=642
x=214
So your numbers are 214, 222 and 314

6 0

3 years ago

Represent the following sentence as an algebraic expression, where "a number" is the letter x.

oksano4ka [1.4K]

7+x is the awnser

unless you meant to type “A number is more than 7” then it would be x>7

7 0

2 years ago

Read 2 more answers

How do you simplify on number 1?

Dennis_Churaev [7]

Okay. On the part that's not the whole number, see how the top number is BIGGER than the bottom? That means that it's not simplified. In order to make it simplified, you have to take a whole out of the pat that's not a whole number. Since the denominator is 12, the whole is 12/12. So, subtract it from the 13/12.

13/12-12/12=1/12

Now, since you found a whole inside of the fraction you have to add 1 to the whole number.
5+1=6

So, the answer is 6 1/12.

Thanks for the points!

6 0

3 years ago