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tigry1 [53]
3 years ago
8

Maya has 5/6 cup of ice cream. how many 1/4 cup servings are in 5/6 cup of ice cream

Mathematics
1 answer:
yulyashka [42]3 years ago
6 0
Find the LCD (least common denominator)
\frac{5}{6}  and  \frac{1}{4}

it would be 12 (6x2=12 and 4x3=12)

so you multiply \frac{5}{6} by 2 and get \frac{10}{12}
then multiply \frac{1}{4} by 3 and get \frac{3}{12}

you get 3 WHOLE servings from \frac{5}{6} cups of icecream
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A karat equals 1/24 part of gold in an alloy [ eg 9 karat gold is 9/24 gold]. How many grams of 9 karat gold must be mixed with
irinina [24]
This is a mixture problem.

Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.

mass1 * karat1 + mass2*karat = total mass * total carat

Let mass1 be x g.          mass 2 would be = (200 -x)
karat 1 = 9                    karat 2 = 18 

Total mass = 200g.
Total karat = 14.

9*x  + 18*(200 -x) = 14*200

9x + 18*200 - 18*x = 14*200

18*200 + 9x - 18x = 14*200

3600 - 9x = 2800

3600 - 2800 = 9x

800 = 9x

9x = 800

x = 800/9

x ≈ 88.89

Therefore 88.89 grams of 9 karat gold must be mixed.
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Step-by-step explanation:

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Pedro has simplified 4/7 ÷ 5/8
Scorpion4ik [409]

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are u suppose to find a common denominator when multiplying fractions? (dont answer the question in the picture just answer if u
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