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pantera1 [17]
3 years ago
12

Differentable surface waves from body waves?

Chemistry
1 answer:
kodGreya [7K]3 years ago
6 0

Body waves travel through the interior of the Earth. On the other hand, surface waves propagate only at the interface between two different media, like the interface between Earth and atmosphere (i.e. the surface of the Earth).

Body waves are of two types: Primary waves (also called P-waves, or pressure waves) and Secondary waves (S-waves, or shear waves).

P-waves are compression waves. They can propagate in solid or liquid material.

S-waves are shear waves. They only propagate in solid material.

By studying the trajectories of S-waves, scientists could prove that the Earth had a liquid outer core.


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Find the molarity and molality of 37.0 wt% Hcl. Assume the density of the acid is 1.19g/ml​
erik [133]

Answer:

a) M HCl = 32.162 mol/L

b) m HCl = 15.873 mol/Kg

Explanation:

  • wt% = (mass HCl / mass sln)×100
  • δ HCl = mass HCl / Volume sln
  • molarity = mol HCl / V sln (L)
  • molality = mol HCl / Kg solvent

∴ MW HCl = 36.46 g/mol

assuming mass sln = 1 g

∴ mass sln = 1 g = g solvent + g solute

∴ solute: HCl

⇒ 0.37 = g HCl / g sln

⇒ g HCl = 0.37 g

⇒ g ste = 1 - 0.37 = 0.63 g

⇒ Kg ste = (0.63 g)×(Kg/1000 g) = 6.3 E-4 Kg

⇒ mol HCl = (0.37 g HCl)×(mol/36.46 g HCl) = 0.010 mol HCl

∴ V sln = (0.37 g)/(1.19 g/mL) = 0.3109 mL

⇒ V sln = (0.31 mL)×( L/1000 mL) = 3.109 E-4 L

a) molarity (M):

⇒ M HCl = 0.010 mol HCl / 3.109 E-4 L

⇒ M HCl = 32.162 mol/L

b) molality (m):

⇒ m HCl = ( 0.010 mol HCl) / (6.3 E-4 Kg)

⇒ m HCl = 15.873 mol/Kg

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The main use of calcium sulphate,specifically in hospitals,is plaster of paris cast.The powdered form of CaSO4 can be formed into a moldable paste upon hydration.

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