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lora16 [44]
3 years ago
11

The sun is more massive than the moon, but the sun is farther from the earth.? The sun is more massive than the moon, but the su

n is farther from the earth. Which one exerts a greater gravitational force on a person standing on the earth? Give your answer by determining the ratio Fsun/Fmoon of the magnitudes of the gravitational forces.
Physics
1 answer:
Juli2301 [7.4K]3 years ago
7 0
It would be the sun (my answer for it was 177.0)

You might be interested in
A mass M is attached to an ideal massless spring. When this system is set in motion with amplitude A, it has a period T. What is
frutty [35]
<h2>Option B is the correct answer.</h2>

Explanation:

Period of a spring mass arrangement is given by

                   T=2\pi\sqrt{\frac{m}{k}}

       where m is mass and k is spring constant.

So period of spring mass arrangement is independent of amplitude of motion.

Here amplitude changes from A to 2A.

Period for amplitude A is given by T.

Since period remains same for amplitude 2A also, the period is T.

Option B is the correct answer.

6 0
3 years ago
In a Rutherford scattering experiment, an alpha particle is accelerated toward a stationary silver nucleus. If the closest appro
lys-0071 [83]

Answer:

Initial Kinetic energy of alpha particle is  9.45x10⁻¹³ J .

Explanation:

The distance at which the initial kinetic energy of the particle is equal to the potential energy is known as closest distance. As it is Rutherford scattering, so it is a coulomb potential energy.

Let K be the initial kinetic energy of alpha particle and r be the closest approach distance. So,

Initial Kinetic Energy = Coulomb Potential Energy

K = \frac{k\times2e\times{Ze}}{r }

Here, k is constant, e is charge of electron and Z is the atomic number of silver.

Put 9x10⁹ N m²/C² for k, 1.6x10⁻¹⁹ C for e, 47 for Z and 22.9x10⁻¹⁵ m for r in the above equation.

K = \frac{9\times10^{9}\times{1.6}\times10^{-19}\times{1.6}\times10^{-19}\times2\times47}{22.9\times10^{-15} }

K = 9.45x10⁻¹³ J

3 0
4 years ago
A substance of unknown mass absorbs 138 kilojoules of energy, going from 298 to 303 kelvin. if the specific heat of the substanc
AveGali [126]

Heat absorbed to raise the temperature is given by

Q = mc\Delta T

here

m = mass

c = 7.11 J/g C

\Delta T = 303 - 298 = 5 kelvin

Q = 138 KJ

Now by using the above formula we will have

138 * 10^3 = m* 7.11 * 5

m = 3881 gram

m = 3.88 kg

So the amount of the substance will be 3.88 kg

4 0
4 years ago
While filming an intense action sequence for the next James Bond movie, a controlled explosion detonates 1.3 km away from the ac
brilliants [131]

To solve this problem we must basically resort to the kinematic equations of movement. For which speed is defined as the distance traveled in a given time. Mathematically this can be expressed as

v = \frac{d}{t}

Where

d = Distance

t = time

For which clearing the time we will have the expression

t = \frac{d}{v}

Since we have two 'fluids' in which the sound travels at different speeds we will have that for the rock the time elapsed to feel the explosion will be:

t = \frac{1300m}{3000m/s}

t = 0.433s

In the case of the atmosphere -composite of air- the average speed of sound is 343m / s, therefore it will take

t = \frac{1300m}{343m/s}

t = 3.79s

The total difference between the two times would be

\Delta t = 3.79s-0.433s

\Delta t = 3.357s

Therefore 3.357s will pass between when they feel the explosion and when they hear it

8 0
4 years ago
A car and driver weighing 5060N passes a sign stating "Bridge out 27.5 meters ahead." She slams on the brakes and the car decele
OlgaM077 [116]

Answer:

<u>198785.714286 Joules</u>

Explanation:

W=f*d

F=ma\\F=516.326530612*-14\\F=-7228.57142857 N\\

<u>To find work:</u>

Now that the force and the distance are known, plug and chug:

W=f*d\\W=-7228.57142857*27.5\\W=-198785.714286J

Note that the question is asking for the magnitude of work, so the negative can be discarded as it is a directional component.

So, your answer is

<u>198785.714286 Joules</u>

6 0
3 years ago
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