In a moving car the outside looks to be moving. however if viewed from the outside, the car appears to be moving. so motion is relative to the person observing.
Answer:
Explanation:
Vm = Δs/Δt
700km/h = Δs/1.5h
700 = Δs/1.5

S = 700 x 1.5
S = 1050 Km
*(S = Δs)
Answer: The rocket will have traveled 1050 Km
Hope this help ☺
Any ride that oscillates back and forth or moves only in a complete circle utilizes periodic motion.
Explanation:
Given that,
Mass of the ball, m = 1.2 kg
Initial speed of the ball, u = 10 m/s
Height of the floor from ground, h = 32 m
(a) Let v is the final speed of the ball. It can be calculated using the conservation of energy as :



v = -25.04 m/s (negative as it rebounds)
The impulse acting on the ball is equal to the change in momentum. It can be calculated as :


J = -42.048 kg-m/s
(b) Time of contact, t = 0.02 s
Let F is the average force on the floor from by the ball. Impulse acting on an object is given by :



F = 0.8409 N
Hence, this is the required solution.