Answer:
Without units, the results are unclear and it is hard to keep track of what each seperate measurement entails.
1. The speed in kilometers per hour (Km/h) is 133.2 Km/h
2. Yes, the speed is exceeding the 125 Km/h limit
<h3>How to convert 37 m/s to Km/h</h3>
From the question given above, the following data were obtained:
- Speed (in m/s) = 37 m/s
- Speed (in Km/h) =?
We can convert 37 m/s to kilometers per hour (Km/h) by doing the following:
1 m/s = 3.6 Km/h
Therefore,
37 m/s = 37 × 3.6
37 m/s = 133.2 Km/h
Thus, 37 m/s is equivalent to 133.2 Km/h
<h3>2. How to determine if the speed is exceeding the limit</h3>
- Speed of car = 133.2 Km/h
- Speed limit = 125 Km/h
From the above, we can see that the speed of the car is greater than the speed limit.
Thus, we can conclude that the speed of the car is exceeding the speed limit.
Learn more about conversion:
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Answer:
Explanation:
Since there is no friction angular momentum is conserved. The formula for angular momentum thet will be useful in this case is 
. If we call 1 the situation when the student is at the rim and 2 the situation when the student is at 
from the center, then we have:
Or:
And we want to calculate:
The total moment of inertia will be the sum of the moment of intertia of the disk of mass 
and radius 
, which is 
, and the moment of intertia of the student of mass 
at position 
(which will be 
or ) will be 
, so we will have:
or:
which for our values is:
Answer:
v = √k/m x
Explanation:
We can solve this exercise using the energy conservation relationships
starting point. Fully compressed spring
Em₀ = 
= ½ k x²
final point. Cart after leaving the spring
= K = ½ m v²
Em₀ = Em_{f}
½ k x² = ½ m v²
v = √k/m x
Hello,
The mass number is protons+neutrons=mass number. In this case, we have protons+nuetron=164.The atomic number is simply the number of protons so we have 43+neutrons=164. Subtracting 43 from both sides we get nuetrons=121. Hope this helps!
