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liq [111]
3 years ago
7

Can some1 help me with this please

Mathematics
2 answers:
ziro4ka [17]3 years ago
5 0
Y=2x+5 is the answer
Mrac [35]3 years ago
3 0

Answer:

y = 5 - 5/3x I think that's the answer

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Answer:

The volume of the cone is 25.13, the other one is 167.55

Step-by-step explanation:

v = 1/3pi(2)^2(6)

simplify and divide the above.

v = 25.13

1/3pi(4)^2(10)

= 167.55

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3 years ago
What is the value of x in the equation below?
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Step-by-step explanation:

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3 years ago
60 is 150% of what in math
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40% is the answer to your question.

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3 years ago
The length of a rectangle is 12 cm more than its width. Find the
just olya [345]

Dimensions of the rectangle (width and length) are 19 cm and 31 cm respectively.

Step-by-step explanation:

  • Step 1: Given that the perimeter = 100 cm, let width be x cm and then length = 12 + x.

Perimeter of a rectangle = 2(length + width)

100 = 2(x + 12 + x)

100 = 4x + 24

4x = 100 - 24 = 76

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5 0
3 years ago
The average maximum monthly temperature in Campinas, Brazil is 29.9 degrees Celsius. The standard deviation in maximum monthly t
velikii [3]

Answer:

3.84% of months would have a maximum temperature of 34 degrees or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 29.9, \sigma = 2.31

What percentage of months would have a maximum temperature of 34 degrees or higher?

This is 1 subtracted by the pvalue of Z when X = 34. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{34 - 29.9}{2.31}

Z = 1.77

Z = 1.77 has a pvalue of 0.9616

1 - 0.9616 = 0.0384

3.84% of months would have a maximum temperature of 34 degrees or higher

8 0
3 years ago
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