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miss Akunina [59]
2 years ago
5

Kevin invest $2,000 at 4.6% compounded continuously. How long will it take him to have $3,700

Mathematics
1 answer:
natali 33 [55]2 years ago
6 0

Answer:

t=In(37/20)/0.046

Step-by-step explanation:

p=2000

r=0.046

A=3700

t=?

3700=2000e^0.046t

switch sides

2000e^0.046t=3700

Divide both sides by 2000

$2000e^0.046t/2000=$3700/2000

Simplify

e^0.046=37/20

Apply exponent rules

0.046=37/20

Solve 0.046t = ln(37/20)

t=In(37/20)/0.046

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Step-by-step explanation:

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Which expression is equivalent to...? Screenshots attached. Please help! Thank you.
Studentka2010 [4]

Answer:

4x^{3} y^{2} (\sqrt[3]{4 x y})

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }

Then we'll extract the 4 from the cubic root.  We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}

The answer is then:

4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})

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Answer:

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Step-by-step explanation:

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