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maw [93]
3 years ago
6

A 70 cm long stick is cut into two parts in such a way that the longer part is 20 cm longer than the shorter part. How long is e

ach part?
Mathematics
1 answer:
Dahasolnce [82]3 years ago
5 0

Answer:

Long part= 45

Short part= 25

Step-by-step explanation:

Let the short part of the stick be x

Let the long part be x+20

The total length of the stick is 70cm

x + (x+20)= 70

x+x+20= 70

2x+20= 70

2x= 70-20

2x= 50

x= 50/2

= 25

Longer part length= 20+25

= 45

The short part is 25

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There are 3 people pulling on an object, the first person pulls with a force of 226 newtons at a direction of 145 degrees the se
Alona [7]

Answer:

R=883.74N

Step-by-step explanation:

From the question we are told that:

Force 1 F_1=226N

Force 2 F_2=331N

Force 3 F_3=377N

Direction 1  \theta_1=145 degrees \approx 35 \textdegree (2nd qudrant)

Direction 2 \theta_2=303 degrees \approx 57 \textdegree (3rd qudrant)

Direction 3 \theta_3=77 degrees

Generally Resolving forces to X axis is mathematically given by

 \sum f_x=337cos77+331cos57+226sin35

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Generally Resolving forces to Y axis is mathematically given by

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Generally the equation for Resultant force R is mathematically given by

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 R=883.74N

7 0
3 years ago
In triangle $ABC,$ point $D$ is on $\overline{AC}$ such that $AD = 3CD = 12$. If $\angle ABC = \angle BDA = 90^\circ$, then what
Neporo4naja [7]

Answer:

BD=4\sqrt{3}\ units

Step-by-step explanation:

we know that

AD=12\ units

3CD=12 ----> CD=4\ units

see the attached figure to better understand the problem

Triangles ABD and BCD are similar by AA Similarity Theorem

Remember that

If two figures are similar, then the ratio of its corresponding sides is proportional

so

\frac{BD}{AD}=\frac{CD}{BD}

substitute the given values

\frac{BD}{12}=\frac{4}{BD}

BD^2=48

BD=\sqrt{48}\ units

simplify

BD=4\sqrt{3}\ units

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Answer:

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Step-by-step explanation:

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f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}

We use binomial expansion for (x+h)^{\frac{1}{2}}

This can be rewritten as

[x(1+\dfrac{h}{x})]^{\frac{1}{2}}

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From the expansion

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