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s344n2d4d5 [400]
3 years ago
14

Based on a​ survey, when 1009 consumers were asked if they are comfortable with drones delivering their​ purchases, 42% said yes

. The probability of randomly selecting 30 of the 1009 consumers and getting exactly 24 who are comfortable with the drones is represented as 0plus. What does 0plus ​indicate? Does 0plus indicate that it is impossible to get exactly 24 consumers who are comfortable with​ drones?Choose the correct answer below.
A.The probability 0+ indicates that the probability is a very small positive value. It indicates that the event is impossible.
B.The probability 0+ indicates that the probability is a very small positive value. It indicates that the event is​ possible, but very unlikely.
C.The probability 0+ indicates that the probability is a very small positive value. It indicates that the event is likely.
D.The probability 0+ indicates that the probability is zero. It indicates that the event is impossible.
Mathematics
1 answer:
Darina [25.2K]3 years ago
6 0

Answer:

B.The probability 0+ indicates that the probability is a very small positive value. It indicates that the event is​ possible, but very unlikely.

Step-by-step explanation:

Out of 1009 consumers a sample of 30 consumers is selected and asked the questions. So, the sample size is 30.

n = 30

Based on previous survey, 42% are comfortable with the drone. So in this sample, we can consider the probability of success to be 42%.

p = 42% = 0.42

q = 1 - p = 1 - 0.42 = 0.58

We want to find the probability of getting exactly 24 consumers who are comfortable with drones.

x = 24

Since, the sample size is fixed, the selections are independent and probability of success is constant, we can use the Binomial Probability to answer this problem. All the conditions of a Binomial Distribution are being satisfied.

According to the formula of Binomial Distribution, the probability of getting exactly x success among n trials is given as:

P( X = x )=^{n}C_{x}(p)^{x}(q)^{n-x}

Using the values, we get:

P(X = 24) =^{30}C_{24}(0.42)^{24}(0.58)^{6}= 0.00002

Thus, the probability of getting exactly 24 consumers from a sample of 30 who are comfortable with drones is 0.00002, which is extremely small.

Since, the value of probability is a very small positive number, it indicates that event is possible but very unlikely. An impossible event has probability equal to 0.

Therefore, option B gives the correct answer.

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Starting in the 1970s, medical technology allowed babies with very low birth weight (VLBW, less than 1500 grams, about 3.3 pound
cluponka [151]

Answer:

The test statistic value using the VLBW babies as group 1 is z=-2.76±0.01 and the P-value for the test (±0.0001) is 0.0030.

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

The significance level is 0.05.

The sample 1 (VLBW group), of size n1=244 has a proportion of p1=0.77049.

p_1=X_1/n_1=188/244=0.77049

The sample 2 (control group), of size n2=247 has a proportion of p2=0.79757.

p_2=X_2/n_2=197/247=0.79757

The difference between proportions is (p1-p2)=-0.02708.

p_d=p_1-p_2=0.77049-0.79757=-0.02708

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{188+197}{244+247}=\dfrac{385}{491}=0.988

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.988*0.012}{244}+\dfrac{0.988*0.012}{247}}\\\\\\s_{p1-p2}=\sqrt{0.00005+0.00005}=\sqrt{0.0001}=0.0098

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.02708-0}{0.0098}=\dfrac{-0.02708}{0.0098}=-2.76

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=P(t

As the P-value (0.0030) is smaller than the significance level (0.05), the effect issignificant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the proportion of persons with normal birth weight that graduates from high school is significantly greater than the proportion of persons with very low birth weight that graduates from high school.

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Answer:

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