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3 years ago

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You are creating a collage of black-and-white and color photographs. Each black-and-white photo costs $3 to print and each color

photo costs $2 to print. You want the collage to have at least 12 photographs, but can not afford to spend more than $36.

1 answer:

Reil [10]3 years ago

7 0

Answer:

6 black and white photos

9 color photos

Step-by-step explanation:

1. black and white photo = $3

2. color photo = $2

find number of each photo that will give you at least 12 photos

1. $3*6 = $18

2. $2*9 = $18

3. $36 = 15 photos (6 black and white, 9 color)

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Answer:

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Step-by-step explanation:

A quadratic function is given to us . And we need to fill out the table by using the function . The given function is ,

$\rm\implies y = x^2+x - 6$

Here we need to substitute the different values of x , to get the different values of y.

<u>Put</u><u> </u><u>x </u><u>=</u><u> </u><u>-</u><u>3</u><u> </u><u>:</u><u>-</u><u> </u>

$\rm\implies y = 3^2-3-6\\$

$\rm\implies y = 9 - 3 - 6 \\$

$\rm\implies y = 0$

<u>Put </u><u>x </u><u>=</u><u> </u><u>-</u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

$\rm\implies y = 2^2-2-6\\$

$\rm\implies y = 4 -2-6\\$

$\rm\implies y = -4$

<u>Put</u><u> </u><u>x </u><u>=</u><u> </u><u>-</u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

$\rm\implies y = -1^2-1-6\\$

$\rm\implies y = 1 -1-6 \\$

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<u>Put </u><u>x </u><u>=</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

$\rm\implies y = 1^2+1-6\\$

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$\rm\implies y = 2^2+2-6\\$

$\rm\implies y = 4 +2-6\\$

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$\rm\implies y = 3^2+3-6\\$

$\rm\implies y = 9 +3-6\\$

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Answer:
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