Answer:
Juanita and Esperanza run 400 meters and 8400 meters respectively and Evelyn make 4.125 laps.
Step-by-step explanation:
<u>The complete question is</u>: A telesecundaria school has a race track that measures one kilometer
.
Three students ran the following distances Juanita: 1 laps, Esperanza 21 laps and Evelyn: 1650 m. How many meters did Juanita and Esperanza run? And how many laps did Evelyn make?
As we know that 1 meter = 0.0025 laps
So, the number of laps Evelyn make = 1650 
0.0025
= 4.125 laps
Also, 1 lap = 
meters
1 lap = 400 meters
So, the meters that Juanita run = 1 400 = 400 meters
Similarly, the meters that Esperanza run = 21 400
= 8400 meters
Hence, Juanita and Esperanza run 400 meters and 8400 meters respectively and Evelyn make 4.125 laps.
Answer:
3.2
Step-by-step explanation:
Answer:-2x^2+3x-7=0
Step-by-step explanation:
Answer:
x = -2/5
y = 12/5
Step-by-step explanation:
Substitution method;
-2x + 3y = 8 -----------(i)
x + y =2 -----------(ii)
x = 2 - y
substitute the value of x in equ (i)
(-2)* (2-y) + 3y = 8
-4 + 2y + 3y = 8
5y = 8 + 4
y = 12/5
substitute the value of y in equ (ii)
x + 12/5 = 2
x = 2 - 12/5
= 2*5/1*5 - 12/5
= 10 -12/5 = -2/5
Ans: x = -2/5
y = 12/5
elimination method:
-2x + 3y = 8 -----------(i)
x + y =2 -----------(ii)
(i) ====> -2x + 3y = 8
multiply equ (ii) by 2 ====> <u> 2x + 2y = 4</u>
add (i) and (ii) 5y = 12
y = 12/5
Substitute in equ (ii)
x + 12/5 = 2
x = 2 - 12/5
= 2*5/1*5 - 12/5
= 10 -12/5 = -2/5
Ans: x = -2/5
y = 12/5
Answer:
B) x = 7, y = 4
Step-by-step explanation:
you can find the value of 'y' first by connecting the bases with another altitute measuring 4 units
you now have an isosceles triangle where each leg is 4 which makes the hypotenuse equal to 4
to find 'x', it is the sum of 3 and 4
