Answer:
Yes we can conclude.
Step-by-step explanation:
The sampling distribution of
can be approximated as a Normal Distribution only if:
np and nq are both equal to or greater than 10. i.e.
Both of these conditions must be met in order to approximate the sampling distribution of
as Normal Distribution.
From the given data:
n = 50
p = 0.80
q = 1 - p = 1 - 0.80 = 0.20
np = 50(0.80) = 40
nq = 50(0.20) = 10
This means the conditions that np and nq must be equal to or greater than 10 is being satisfied. So, we can conclude that the sampling distribution of pˆ is approximately a normal distribution
Answer:
43
Step-by-step explanation:
The first three numbers are perfect squares:
9 = 3²
16 = 4²
25 = 5²
43 is not a perfect square.
I hope this helps you
1/21+1/28=1/t
4/84+3/84=1/t
5/84=1/t
t=84/5
84/5 1
21 ?
?.84/5=1.21
?=5/4
Sorry that is wrong, you distribute the 2 to the h and the 8 so it would be 2h-16-h. that would be h-16 on the left side,