Recall that for all t,
cos²(t) + sin²(t) = 1
Now,
x = 5 cos(t) - 7 ⇒ (x + 7)/5 = cos(t)
y = 5 sin(t) + 9 ⇒ (y - 9)/5 = sin(t)
so that substituting into the identity above, we get
((x + 7)/5)² + ((y - 9)/5)² = 1
which we can rewrite as
(x + 7)²/25 + (y - 9)²/25 = 1
(x + 7)² + (y - 9)² = 25
and this is the equation of a circle centered at (-7, 9) with radius 5.
She paid $ 4 for renting a video game for 4 days...that means she paid $ 1 per day.
A horizontal axis is labeled days, a vertical axis is labeled cost of rental.
(x,y)...x is gonna be ur days and y is gonna be ur cost of rental
ur equation is gonna be y = x
points are plotted (1,1) , (2,2), (3,3)
^^ this is the graph u use ...graph B
We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
The answer is g=13 I hope this helped
This is false for example, the GCF of 13 and 26 is 13, an odd number.
