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cluponka [151]
3 years ago
15

Consider the following functions:

Mathematics
1 answer:
inna [77]3 years ago
4 0
33333333333333333333
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Challenge A large university accepts 50% of the students who apply. Of the students the
Monica [59]

Answer:

Step-by-step explanation:

20,000 students 50% are accepted so that is 10,000 students of that 10,000 only 25% enroll which is 2,500.

7 0
3 years ago
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An Impressionist painting increases in value
jok3333 [9.3K]

Answer:

A = $8406.6

Step-by-step explanation:

Given:

Average rate r=9\%

Initial cost of painting a = \$1500

Time t = 20\ years

We need to find the final amount of painting at the end of a 20-year.

Solution:

Using Exponential Growth rate formula as:

A = a(1+r)^t  ----------(1)

Where:

A = Final amount

a = Initial amount.

r = Rate as a decimal.

t = Time.

Now, we substitute all given values in equation 1.

A = 1500(1+0.09)^{20}

A = 1500(1.09)^{20}

Substitute 1.09^{20} = 5.60 in above equation.

A = 1500\times 5.60

A = $8406.62

Therefore, value of the  painting at the end of  a 20-year A = $8406.6

5 0
4 years ago
A) A rectangle is 8.7 cm long and 5.4 broad.
Mama L [17]

Step-by-step explanation:

a)i) perimeter= side+side+side+side

perimeter=8.7+8.7+5.4+5.4=28.2cm

ii) area=h×b

area=8.7×5.4=46.98cm²

b)i) perimeter=20.35+20.35+17.84+17.84

perimeter=76.38cm

ii)area=20.35×17.84

area=363.044cm²

c) area of rectangular field=937.125m²

Length=36.75m

i)Breadth=937.125÷36.75=25.5m

ii)perimeter=36.75+36.75+25.5+25.5

perimeter=124.5m

8 0
3 years ago
At the burger place, 3 mini hamburgers fit in each small to-go bag. if the baldwin family ordered 41 mini hamburgers for the tri
arsen [322]

How man bags were used?

41 / 3 = 13.7

We can say about 14 bags by rounding to the nearest whole number. Therefore, 14 bags were used.

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3 years ago
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Sam invested $48,000 some at 6% interest and the rest at 10% . How much did he invest at each rate if he received $4,000 in inte
emmainna [20.7K]

<u>Answer with step-by-step explanation:</u>

We are given that Sam invested $48,000 at 6% interest and the rest at 10%. Given that he received $4,000 interest in one year, we are to find how much he invest at each rate.

Assuming the amount invested at 6% interest rate as x, we can write it as:

(\frac{6}{100} \times x)+(\frac{10}{100} \times [48000-x])=4000

0.06x+0.1(48000-x)=4000

0.06x+4800-0.1x=4000

0.1x-0.06x=4800-4000

0.04x=800

x=20000

So the amount invested at 6% = $20,000 and amount invested at 10% = (48000 - 20000) = $28,000

3 0
3 years ago
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