Answer:
Step-by-step explanation:
20,000 students 50% are accepted so that is 10,000 students of that 10,000 only 25% enroll which is 2,500.
Answer:
A = $8406.6
Step-by-step explanation:
Given:
Average rate 
Initial cost of painting 
Time 
We need to find the final amount of painting at the end of a 20-year.
Solution:
Using Exponential Growth rate formula as:
----------(1)
Where:
A = Final amount
a = Initial amount.
r = Rate as a decimal.
t = Time.
Now, we substitute all given values in equation 1.


Substitute
in above equation.

A = $8406.62
Therefore, value of the painting at the end of a 20-year A = $8406.6
Step-by-step explanation:
a)i) perimeter= side+side+side+side
perimeter=8.7+8.7+5.4+5.4=28.2cm
ii) area=h×b
area=8.7×5.4=46.98cm²
b)i) perimeter=20.35+20.35+17.84+17.84
perimeter=76.38cm
ii)area=20.35×17.84
area=363.044cm²
c) area of rectangular field=937.125m²
Length=36.75m
i)Breadth=937.125÷36.75=25.5m
ii)perimeter=36.75+36.75+25.5+25.5
perimeter=124.5m
How man bags were used?
41 / 3 = 13.7
We can say about 14 bags by rounding to the nearest whole number. Therefore, 14 bags were used.
<u>Answer with step-by-step explanation:</u>
We are given that Sam invested $48,000 at 6% interest and the rest at 10%. Given that he received $4,000 interest in one year, we are to find how much he invest at each rate.
Assuming the amount invested at 6% interest rate as
, we can write it as:
![(\frac{6}{100} \times x)+(\frac{10}{100} \times [48000-x])=4000](https://tex.z-dn.net/?f=%28%5Cfrac%7B6%7D%7B100%7D%20%5Ctimes%20x%29%2B%28%5Cfrac%7B10%7D%7B100%7D%20%5Ctimes%20%5B48000-x%5D%29%3D4000)





So the amount invested at 6% = $20,000 and amount invested at 10% = (48000 - 20000) = $28,000