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nikitadnepr [17]
3 years ago
15

Area between two shapes. IXL Geometry help pls ! (will mark the brainiest)

Mathematics
1 answer:
Sedaia [141]3 years ago
4 0

Answer: the shaded region is 1138.97m²

Step-by-step explanation:

The formula for determining the area of a circle is expressed as

Area = πr²

Where

r represents the radius of the circle.

π is a constant whose value is 3.14

Considering the larger circle,

Radius = 11.6 + 10.7 = 22.3 m

Area = 3.14 × 22.3² = 1561.4906m²

Considering the smaller circle,

Radius = 11.6 m

Area = 3.14 × 11.6² = 422.5184m²

Area of the shaded region is area of the larger circle - area of the smaller circle. It becomes

1561.4906 - 422.5184 = 1138.97m² rounded up to the nearest hundredth

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y intercept is 5. x intercept is 5/7

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In how many different ways can seven children line up in one row to have their picture taken?
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Draw a number line that shows the distance between 3 and -2 is 5
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This is how I would do it, hope this helps!

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The ages of three siblings Jason John and Jackson totals 21 years. Jason is one year older than John. Jackson is three times as
Ymorist [56]

Answer:Jason is 5 years old.

John is 4 years old.

Jackson is 12 years old.

Step-by-step explanation:

Let x represent the age of Jason.

Let y represent the age of John.

Let z represent the age of Jackson.

The ages of three siblings Jason John and Jackson totals 21 years. It means that

x + y + z = 21 - - - - - - - - - - -1

Jason is one year older than John. It means that

x = y + 1

Jackson is three times as old as John. It means that

z = 3y

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y + 1 + y + 3y = 21

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6 0
3 years ago
A city planner designs a park that is a quadrilateral with vertices at J(−1, 1), K(1, 3), L(5, −1), and M(−3, −1). There is an e
Vadim26 [7]

use the eqn below to find the mid-pts

x-mid-pt = (x₁+x₂)/2

y-mid-pt = (y₁+y₂)/2

J(−1, 1), K(1, 3), L(5, −1), and M(−3, −1)

So

midpoint JK = (-1+1/2, 1+3/2) = (0,2)

midpoint KL = (1+5/2, 3+⁻1/2) = (3,1)

midpoint LM = (5+⁻3/2, ⁻1+⁻1/2) = (1,-1)

midpoint MJ = (⁻3+⁻1/2, -1+1/2) = (-2,0)


use the eqn to find distance:


d = √(x₂ - x₁)² + (y₂ - y₁)²


Distance between JK and LM = √(0⁻1)² + (2 - ⁻1)² = √1 + 9 = √10

Distance between JM and KL = √(3-⁻2)² + (1-0)² = √25 + 1 = √26

Scale is 10

Actual distance = 10*(√10 + √26) = 82.6 = 83 units


8 0
3 years ago
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