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Ganezh [65]
3 years ago
6

Find the values of the following, giving your answers as fractions 4^(-1) 2^(-3) 3^(-4)

Mathematics
1 answer:
pogonyaev3 years ago
6 0

Fractions

The values are  \frac{1}{4}  , \frac{1}{8} , \frac{1}{81}

Step-by-step explanation:

As we know the fractions whose numerators are 1 can be represented in exponents and vice versa provided that the power of the exponent is (-1) ,

like 1/a = a^(-1)  

\frac{1}{a}  = a^{-1}

so accordingly

a)

   4^(-1) or 4^{-1} can be represented exponentially as ¼ .

⇒   \frac{1}{4}

Part b)

2^(-3)  or 2^{-3}

We can simplify the exponent so that the power should be equal to -1.

And, so 2^{3} = 8

So we can write the above the expression as 8^(-1)  or 8^{-1}

So the fraction corresponding to it is \frac{1}{8}.

⇒ \frac{1}{8}

Part c)

3^(-4) now we  can simplify the exponent so that the power of the exponent is -1.

And thus , (3 ^4)^(-1) = 81^(-1)  = \frac{1}{81}

So the fraction obtained is \frac{1}{81}.

⇒ \frac{1}{81}

The values are  \frac{1}{4}  , \frac{1}{8} , \frac{1}{81}

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Consider a rectangle such that the length of the rectangle is 12 more than thrice its width. Find a formula for the length in terms of its width. Take width as 'x'.

Step-by-step explanation:

Consider a rectangle such that the length of the rectangle is 12 more than thrice its width. Find a formula for the length in terms of its width.

Let the width be 'x'.

Therefore, as per question, length is 12 more than thrice the width.

Thrice the width means 3x. 12 more means adding 12 to the result.

Therefore, the length of the rectangle is 3x+12

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3 years ago
Find the measures of the requested angles.
Alex777 [14]

Answer:

d. m<ABD = 50°, m<GBC = 47°, m<EBC = 50°, and m<DBG = 83°

Step-by-step explanation:

m<ABF = 47° (given)

m<FBE = 83°

✍️m<ABD + m<ABF + m<FBE = 180° (angles on straight line)

m<ABD + 47° + 83° = 180° (substitution)

m<ABD + 130° = 180°

Subtract 130 from each side

m<ABD = 180° - 130°

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✅m<GBC = 47° (Substitution)

✍️m<EBC = m<ABD (Vertical angles)

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Answer: No.

Step-by-step explanation:

I guess that here we have the statement:

If the sum of two numbers is odd----> can their quotient be an odd number?

first, for n an integer number, we have that:

an odd number can be written as 2n + 1

an even number can be written as 2n.

The sum of two numbers is only odd if one of them is odd and the other even.

Then we have a number that is 2n and other that is 2k + 1, for n and k integer numbers.

Now, let's see if the quotient can also be an odd number.

One way to think this is:

There is an odd number such that when we multiply it by another odd number, the result is an even number?

no, and i can prove it as:

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the product is:

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