F(6)=25(6)+100
f(6)=150+100
f(6)=250
Final answer: $250
33/54 = 44/(a+44)
33(a+44) = 44*54
33a+ 1452 = 2376
33a = 924
a = 28
c = sqrt (33^2 + 44^2)
c = sqrt(1089 + 1936)
c = sqrt(3025)
c = 55
33/54 = 55/(b+55)
33(b+55) = 55*54
33b+ 1815 = 2970
33b = 1155
b = 35
answer
a = 28, b = 35, c = 55
Answer:
4.46cm
Step-by-step explanation:
Volume of a frustum is expressed as;
V = (1/3) * π * h * (r₁² + r₂² + (r₁* r₂))
h is the height of the frustum
r₁ and r₂ are the radii of its ends
V is the volume
Given
V = 9100cm₃
r₁ = 10cm
r₂ = 30cm
Substitute
9100 = (1/3) * (3.14) * h * (10² + 30² + (10* 30))
9100 = 1/2(3.14)*h*(100+900+300)
9100 = 1.57*h*(1300)
9100 = 2,041h
h = 9100/2,041
h = 4.46cm
Hence the height of the cap is 4.46cm