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brilliants [131]
3 years ago
9

Was Google right to have entered the Chinese market the way it did? Did Googleâs mission compel it to create Google.cn? What spe

cifi c aspects of the mission does Google address in making its decision to enter? What other reasons could there have been for entering China? How do Googleâs conclusions fi t with its motto, "Donât be Evil"?
Computers and Technology
1 answer:
yulyashka [42]3 years ago
3 0

Answer / Explanation:

Google was right to have entered the china market the way it did and yes, in my opinion, google mission compelled it to create google.com because through this means, even the Chinese can read and do proper research because the data through this means have been translated to Chinese.

With the understanding that china once operated a commanding economy, the presence of google will create a platform for Chinese to have the luxury to perform research and development thereby gradually pulling down the unacceptable commanding rule.

We also need to understand that part of google mission is to help us transfer data in a safe manner while keeping our data and information safe. However, due to the fact that it discovered a cyber attack from within the country that targeted it, google had to shut down in china.

So in the light of the aforementioned, we can say google conclusion to shut down in china fits well into their mission to protect subscribers data.

You might be interested in
1. Write a program to prompt the user to enter a single character and respond back whether or not the character is valid dna. 2.
Nina [5.8K]

Answer:

Answer 1:

dna = input("Enter DNA type: ")

dna = dna.upper()

print(dna)

if dna == "A" or dna == "B" or dna == "Z":

   print("valid")

else:

   print("invalid")

Answer 2:

rna = input("Enter DNA type: ")

rna = rna.lower()

print(rna)

if rna == "m" or rna == "t" or rna == "r":

   print("valid")

else:

   print("invalid")

Answer 3:

dnaSquence = input("Enter the DNA sequence: ")

type = "valid"

for char in dnaSquence:

   if char not in ["A", "C", "G", "T"]:

       type = "invalid"

       break

print(type)

Answer 4:

rnaSquence = input("Enter the RNA sequence: ")

type = "valid"

for char in rnaSquence:

   if char not in ["A", "C", "G", "U"]:

       type = "invalid"

       break

print("valid")

Explanation:

There are three types of DNA; Type A, Type B and Type Z.

A DNA sequence consists of; A, C, G and T.

There are three types of RNA; mRNA, tRNA and rRNA.

An RNA sequence consists of; A, C, G and U.

Code Explanations:

Code 1:

dna = input("Enter DNA type: ")

dna = dna.upper()

print(dna)

if dna == "A" or dna == "B" or dna == "Z":

   print("valid")

else:

<em>    print("invalid")</em>

  1. prompts and Takes a single character input
  2. converts the character to upper case
  3. compares the input to the DNA types
  4. Prints "valid" for a valid input else prints "invalid"

Code 2:

rna = input("Enter DNA type: ")

rna = rna.lower()

print(rna)

if rna == "m" or rna == "t" or rna == "r":

   print("valid")

else:

<em>    print("invalid")</em>

<em />

  1. prompts and Takes a single character input
  2. converts the character to lower case
  3. compares the input to the RNA types
  4. Prints "valid" for a valid input else prints "invalid"

Code 3:

Answer 3:

dnaSquence = input("Enter the DNA sequence: ")

type = "valid"

for char in dnaSquence:

   if char not in ["A", "C", "G", "T"]:

       type = "invalid"

       break

print(type)

  1. It prompts for a DNA sequence.
  2. Declares a string variable "type" and initializes type to valid.
  3. The FOR loop checks every character in the DNA sequence.
  4. If the character is not in the list [A, C, G, T] type becomes invalid and the loop breaks and the type "invalid" is printed to the screen.
  5. if all the characters are in the list, then type will remain valid and will be printed to the screen.

Code 4:

rnaSquence = input("Enter the RNA sequence: ")

type = "valid"

for char in rnaSquence:

   if char not in ["A", "C", "G", "U"]:

       type = "invalid"

       break

print("valid")

  1. It prompts for a RNA sequence.
  2. Declares a string variable "type" and initializes type to valid.
  3. The FOR loop checks every character in the RNA sequence.
  4. If the character is not in the list [A, C, G, U] type becomes invalid and the loop breaks and the type "invalid" is printed to the screen.
  5. if all the characters are in the list, then type will remain valid and will be printed to the screen.

7 0
3 years ago
Which of the following is not expected of employees' oral communication skills in the workplace? Communicate clearly Use appropr
Paladinen [302]

Answer:

The skill that is not expected of employees' oral communication skills in the workplace is:

Be able to write well

Explanation:

The reason behind this answer is: we are analyzing oral communication skills. Writing is not in oral communication skills. Therefore it is not expected as an employee oral communication skill in the workplace. Also, Communicate clearly is expected in the workplace, use appropriate language is expected in the workplace as formality is desired, and finally communicating under the laws and regulations of the organization is also expected.

4 0
3 years ago
Guys i keep trying to get in touch with brainly but it says "your request could not be submitted" Can someone please help me ?
Ann [662]
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7 0
2 years ago
Read 2 more answers
A DDos attack _____________.
melomori [17]

Answer:

Option (1) the is correct answer for the above question.

Explanation:

"DDos" stands for distributed denial-of-service. It is a type of attack which affects the network route. It disturbs the normal route like a traffic Jam. It operators from some hosts point and act after getting access to the system in an unauthorized way.

It attacks to disturb the service provided by the other system. It authorized the hosts' system and entered into the system to get disturb the routine of the system.

  • Option 1 also suggests the same hence it is a correct option.
  • While option 2 suggests that it is a software, but it is a concept that means to disturb the normal routine of the system and he can get that information access which is transmitted over the signals. hence option 2 is not fit for the question.

4 0
3 years ago
Write a program that first gets a list of integers from input. The input begins with an integer indicating the number of integer
snow_tiger [21]

Answer:

The program implemented in C++ is as follows:

#include <iostream>

#include <vector>

using namespace std;

int main(){

int lenlist;

vector<int> mylist;

cout<<"Length List: ";

cin>>lenlist;

mylist.push_back(lenlist);

int i =0; int num;

while(i<lenlist){

   cin>>num;

   mylist.push_back(num);  

   i++;

}

int min,max;

cout<<"Min: ";  cin>>min;

cout<<"Max: ";  cin>>max;

cout<<"Output!"<<endl;

for(int i=1; i < mylist.size(); i++){

  if(mylist.at(i)>=min && mylist.at(i)<=max){

      cout<<mylist.at(i)<<" ";

  }

}

  return 0;

}

Explanation:

This declares the length of the list as integer

int lenlist;

This declares an integer vector

vector<int> mylist;

This prompts user for length of the list

cout<<"Length List: ";

This gets input of length of the list from the user

cin>>lenlist;

This pushes user input to the vector

mylist.push_back(lenlist);

int i =0; int num;

The following iteration gets user inputs and pushes them into the vector

<em>while(i<lenlist){ </em>

<em>    cin>>num; </em>

<em>    mylist.push_back(num);  </em>

<em>    i++; </em>

<em>} </em>

This declares min and max variables

int min,max;

This prompts user for the lower bound

cout<<"Min: ";  cin>>min;

This prompts user for the upper bound

cout<<"Max: ";  cin>>max;

The following iteration checks for numbers within the lower and upper bound and print the numbers in that range

<em>cout<<"Output!"<<endl; </em>

<em>for(int i=1; i < mylist.size(); i++){ </em>

<em>   if(mylist.at(i)>=min && mylist.at(i)<=max){ </em>

<em>       cout<<mylist.at(i)<<" "; </em>

<em>   } </em>

<em>} </em>

3 0
3 years ago
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