Challenge accepted.
CE / 2 = 3JQ / 7
7(CE) = 2(3JQ)
7CE = 6JQ
/6Q /6Q
7CE
/6Q = J
Answer is A. I ain't fully sure cuz I'm only in grade 9 lol
Answer:
x=4
Step-by-step explanation:
First, you need to isolate the variable and constant terms. So, we need to get rid of 36. To do this, we need to take away 36. Now, we have to do this on the other side. 64-36 is 28. Now, the equation is 7x=28.
To isolate the variable, you divide by 7. Again, do this on the other side. 28/7 is 4. Now we have x=4.
Therefore, the correct answer is 4!
Hope I helped!!!!!
Using the exponential growth formula P = Ae^kt, we can solve for the missing values.
Initially, let us solve for the growth factor k, using the values from 1993 and 1999.
In year 1999:
P = 99 million
A = 94 million
t = 1999 - 1993 = 6
Substituting the values into the equation:
99,000,000 = 94,000,000(e^k(6))
k = 8.6375x10^-3
Obtaining the population in 2005 using values from 1999:
P = ?
A = 99,000,000
k = <span>8.6375x10^-3
t = 2005 - 1999 = 6
Substituting the values into the equation:
P = 99,000,000(e^(</span><span>8.6375x10^-3</span>)(6))
P = 104,265,957.4
Approximating to the nearest million, the population in 2005 is 104 million.
67912 rounded to the nearest 10th is 67910
Well area triangler area is multiplied by 3 after you multiply the other numbers