All categories

2 years ago

What key features are necessary and how they can be used to create the sketch of a polynomial function?

Mathematics

1 answer:

Tomtit [17]2 years ago

4 0

The key features of polynomials are the vertex, axis of symmetry, x and y intercepts.

1. The degree will help you find the end behavior.

2. The vertex shows you where it changes concavity.

3. X and y intercepts give you a couple of points of reference.

4. Axis of symmetry is only applicable to even degree polynomials.

I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

You might be interested in

Circle the value that solutions of the inequality 2x - 3 < -9

velikii [3]

Answer:

x < -3

Step-by-step explanation:

2x - 3 < -9

Add 3 to each side

2x - 3+3 < -9+3

2x < -6

Divide by 2

2x/2 < -6/2

x < -3

5 0

2 years ago

What is the area of the shape given above?!? Someone please help this is due today

LenaWriter [7]

Answer:

15 m

Step-by-step explanation:

First split the shape into a square and a triangle, then find the area of the square by multipliyng the sides to get.

Next find the length of the traignel by subtracting 3 from 9 to get for then find the area of the triangle by multiplying 4 by 3 to get 12 then divide by 2 to get the area which is 6.

Finally add the 9 to the 6 to get 15

3 * 3 = 9

9 - 3 = 4

4 * 3 = 12/2 = 6

6+9=15

7 0

2 years ago

A student bought 34 pencils for school.if he sharpened 16 of the pencils before school whats is his ratio of unsharpened pencils

Sergio [31]

he bought 34 pencils which I suppose aren't already sharpened

so if he sharpens 16 of them just subtract 16 from 34 (34-16) which equals 18

so the ratio would be 16:18

but if u need to simplify it would be 8:9

3 0

2 years ago

New friends? whats 1+1?

wel

Answer:

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

(a) Determine a cubic polynomial with integer coefficients which has $\sqrt[3]{2} + \sqrt[3]{4}$ as a root.

Keith_Richards [23]

Answer:

(a) $x\³ - 6x - 6$

(b) Proved

Step-by-step explanation:

Given

$r = $\sqrt[3]{2} + \sqrt[3]{4}$$ --- the root

Solving (a): The polynomial

A cubic function is represented as:

$f = (a + b)^3$

Expand

$f = a^3 + 3a^2b + 3ab^2 + b^3$

Rewrite as:

$f = a^3 + 3ab(a + b) + b^3$

The root is represented as:

$r=a+b$

By comparison:

$a = $\sqrt[3]{2}$

$b = \sqrt[3]{4}$$

So, we have:

$f = ($\sqrt[3]{2})^3 + 3*$\sqrt[3]{2}*\sqrt[3]{4}$*($\sqrt[3]{2} + \sqrt[3]{4}$) + (\sqrt[3]{4}$)^3$

Expand

$f = 2 + 3*$\sqrt[3]{2*4}*($\sqrt[3]{2} + \sqrt[3]{4}$) + 4$

$f = 2 + 3*$\sqrt[3]{8}*($\sqrt[3]{2} + \sqrt[3]{4}$) + 4$

$f = 2 + 3*2*($\sqrt[3]{2} + \sqrt[3]{4}$) + 4$

$f = 2 + 6($\sqrt[3]{2} + \sqrt[3]{4}$) + 4$

Evaluate like terms

$f = 6 + 6($\sqrt[3]{2} + \sqrt[3]{4}$)$

Recall that: $r = $\sqrt[3]{2} + \sqrt[3]{4}$$

So, we have:

$f = 6 + 6r$

Equate to 0

$f - 6 - 6r = 0$

Rewrite as:

$f - 6r - 6 = 0$

Express as a cubic function

$x^3 - 6x - 6 = 0$

Hence, the cubic polynomial is:

$f(x) = x^3 - 6x - 6$

Solving (b): Prove that r is irrational

The constant term of $x^3 - 6x - 6 = 0$ is -6

The divisors of -6 are: -6,-3,-2,-1,1,2,3,6

Calculate f(x) for each of the above values to calculate the remainder when f(x) is divided by any of the above values

$f(-6) = (-6)^3 - 6*-6 - 6 = -186$

$f(-3) = (-3)^3 - 6*-3 - 6 = -15$

$f(-2) = (-2)^3 - 6*-2 - 6 = -2$

$f(-1) = (-1)^3 - 6*-1 - 6 = -1$

$f(1) = (1)^3 - 6*1 - 6 = -11$

$f(2) = (2)^3 - 6*2 - 6 = -10$

$f(3) = (3)^3 - 6*3 - 6 = 3$

$f(6) = (6)^3 - 6*6 - 6 = 174$

For r to be rational;

The divisors of -6 must divide f(x) without remainder

i.e. Any of the above values must equal 0

Since none equals 0, then r is irrational

3 0

2 years ago