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Ludmilka [50]
3 years ago
10

Rearrange the digit in 3,529.718 to make the largest number possible

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
5 0
9,875.321
---------------
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Find the missing of the triangle Round to the nearest tenth
inessss [21]

Answer:

Step-by-step explanation:

This is a 30°-60°-90° triangle, so its sides are in the ratio 1:√3:2

The side opposite the 90° angle is 11, so the side opposite the 30° angle is 11/2 = 5.5

x is opposite the 60° angle, so its length is 5.5√3 ≅ 9.5 units

7 0
3 years ago
You pick a card at random 2,3,4,5 what is P(2)
Luden [163]

Total possible outcomes = 4

Total no. of favorable outcomes = 2

\sf \: P(2) = total  \: no. of  \: favorable  \: outcomes/ total  \: no. \:  of  \: possible  \: outcomes  \\  =  \frac{2}{4}  \\  =  \frac{1}{2}

8 0
3 years ago
Read 2 more answers
Find the area of a triangle bounded by the y-axis, the line f(x)=9−4/7x, and the line perpendicular to f(x) that passes through
Setler79 [48]

<u>ANSWER:  </u>

The area of the triangle bounded by the y-axis is  \frac{7938}{4225} \sqrt{65} \text { unit }^{2}

<u>SOLUTION:</u>

Given, f(x)=9-\frac{-4}{7} x

Consider f(x) = y. Hence we get

f(x)=9-\frac{-4}{7} x --- eqn 1

y=9-\frac{4}{7} x

On rewriting the terms we get

4x + 7y – 63 = 0

As the triangle is bounded by two perpendicular lines, it is an right angle triangle with y-axis as hypotenuse.

Area of right angle triangle = \frac{1}{ab} where a, b are lengths of sides other than hypotenuse.

So, we need find length of f(x) and its perpendicular line.

First let us find perpendicular line equation.

Slope of f(x) = \frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-4}{7}

So, slope of perpendicular line = \frac{-1}{\text {slope of } f(x)}=\frac{7}{4}

Perpendicular line is passing through origin(0,0).So by using point slope formula,

y-y_{1}=m\left(x-x_{1}\right)

Where m is the slope and \left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)

y-0=\frac{7}{4}(x-0)

y=\frac{7}{4} x --- eqn 2

4y = 7x

7x – 4y = 0  

now, let us find the vertices of triangle, one of them is origin, second one is point of intersection of y-axis and f(x)

for points on y-axis x will be zero, to get y value, put x =0 int f(x)

0 + 7y – 63 = 0

7y = 63

y = 9

Hence, the point of intersection is (0, 9)

Third vertex is point of intersection of f(x) and its perpendicular line.

So, solve (1) and (2)

\begin{array}{l}{9-\frac{4}{7} x=\frac{7}{4} x} \\\\ {9 \times 4-\frac{4 \times 4}{7} x=7 x} \\\\ {36 \times 7-16 x=7 \times 7 x} \\\\ {252-16 x=49 x} \\\\ {49 x+16 x=252} \\\\ {65 x=252} \\\\ {x=\frac{252}{65}}\end{array}

Put x value in (2)

\begin{array}{l}{y=\frac{7}{4} \times \frac{252}{65}} \\\\ {y=\frac{441}{65}}\end{array}

So, the point of intersection is \left(\frac{252}{65}, \frac{441}{65}\right)

Length of f(x) is distance between \left(\frac{252}{65}, \frac{441}{65}\right) and (0,9)

\begin{aligned} \text { Length } &=\sqrt{\left(0-\frac{252}{65}\right)^{2}+\left(9-\frac{441}{65}\right)^{2}} \\ &=\sqrt{\left(\frac{252}{65}\right)^{2}+0} \\ &=\frac{252}{65} \end{aligned}

Now, length of perpendicular of f(x) is distance between \left(\frac{252}{65}, \frac{441}{65}\right) \text { and }(0,0)

\begin{aligned} \text { Length } &=\sqrt{\left(0-\frac{252}{65}\right)^{2}+\left(0-\frac{441}{65}\right)^{2}} \\ &=\sqrt{\left(\frac{252}{65}\right)^{2}+\left(\frac{441}{65}\right)^{2}} \\ &=\frac{\sqrt{(12 \times 21)^{2}+(21 \times 21)^{2}}}{65} \\ &=\frac{63}{65} \sqrt{65} \end{aligned}

Now, area of right angle triangle = \frac{1}{2} \times \frac{252}{65} \times \frac{63}{65} \sqrt{65}

=\frac{7938}{4225} \sqrt{65} \text { unit }^{2}

Hence, the area of the triangle is \frac{7938}{4225} \sqrt{65} \text { unit }^{2}

8 0
3 years ago
Isabella has dance class every 3 days and soccer
Nataliya [291]

Answer:

15

Step-by-step explanation:

first you need to find the LCM (least common multiple) which is 15 so then every 15 days she will have both soccer, dance class and swimming class on the same day

4 0
3 years ago
Find the surface area and volume of a cylinder with a diameter equal
dangina [55]

Answer:

Volume = 1539.38 cm³

Surface Area = 747.7 cm²

Step-by-step explanation:

Volume = πr² h

V = π(7)²(10)

V = π(49)(10)

V = 490π

V = 1539.38 cm³

Surface Area = 2πrh + 2πr²

SA = 2π(7)(10) + 2π(7)²

SA = 2π(70) + 2π(49)

SA = 140π + 98π

SA = 238π

SA = 747.7 cm²

8 0
2 years ago
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