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3 years ago

Please help me with this problem..........

Mathematics

2 answers:

vaieri [72.5K]3 years ago

6 0

Answer:

y= 2/3x + 3

Step-by-step explanation: I suggest to look up slope intercept calculator it really helps.

marysya [2.9K]3 years ago

4 0

Answer:

y = $\frac{2}{3}$ x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange - 2x + 3y = 9 into this form

Add 2x to both sides

3y = 2x + 9 ( divide all 3 terms by 3 )

y = $\frac{2}{3}$ x + 3 ← in slope- intercept form

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A=h(b+c)
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b=(A/h)-c

Answer: b=(A/h)-c

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3 years ago

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Solve the equation by completing the square. Round to the nearest hundreth if necessary. x^2-x-7=0

gregori [183]

X^2 - x = 7
(x - 0.5)^2 - 0.25 = 7
(x - 0.5)^2 = 7.25
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8 0

3 years ago

use green's theorem to evaluate the line integral along the given positively oriented curve. c 9y3 dx − 9x3 dy, c is the circle

Rina8888 [55]

The line integral along the given positively oriented curve is -216π. Using green's theorem, the required value is calculated.

<h3>What is green's theorem?</h3>

The theorem states that,

$\int_CPdx+Qdy = \int\int_D(\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y})dx dy$

Where C is the curve.

<h3>Calculation:</h3>

The given line integral is

$\int_C9y^3dx-9x^3dy$

Where curve C is a circle x² + y² = 4;

Applying green's theorem,

P = 9y³; Q = -9x³

Then,

$\frac{\partial P}{\partial y} = \frac{\partial 9y^3}{\partial y} = 27y^2$

$\frac{\partial Q}{\partial x} = \frac{\partial -9x^3}{\partial x} = 27x^2$

$\int_C9y^3dx-9x^3dy = \int\int_D(-27x^2 - 27y^2)dx dy$

⇒ $-27\int\int_D(x^2 + y^2)dx dy$

Since it is given that the curve is a circle i.e., x² + y² = 2², then changing the limits as

0 ≤ r ≤ 2; and 0 ≤ θ ≤ 2π

Then the integral becomes

$-27\int\limits^{2\pi}_0\int\limits^2_0r^2. r dr d\theta$

⇒ $-27\int\limits^{2\pi}_0\int\limits^2_0 r^3dr d\theta$

⇒ $-27\int\limits^{2\pi}_0 (r^4/4)|_0^2 d\theta$

⇒ $-27\int\limits^{2\pi}_0 (16/4) d\theta$

⇒ $-108\int\limits^{2\pi}_0 d\theta$

⇒ $-108[2\pi - 0]$

⇒ -216π

Therefore, the required value is -216π.

Learn more about green's theorem here:

brainly.com/question/23265902

#SPJ4

3 0

2 years ago

97+(-27)+(-89)+(-54)

RUDIKE [14]

Step 1:

$97+(-27)+(-89)+(-54)$

Step 2:

$= 97 - 27 - 89 - 54$

Info:

(+) ×(-)=-

Step 3:

$= 97 - 170$

Step 4:

$= - 73✓$

8 0

3 years ago