This is the standard for of seven hundred (700) thirty (30) one (1) :
Answer: 731
Answer:
Step-by-step explanation:
x^3 - 8x² - x + 8 =0
x^3 - 8x² - (x - 8 )=0
x²(x-8) - (x-8) = 0
(x-8)(x² -1) =0
x-8 = 0 or x² - 1 = 0
x-8=0 or (x-1)(x+1)=0
x=8 x=1 or x=-1
No because the square root of 128 is 11.3 which it not a whole number or in other words doesnt come out evenly
Factor x as it is a common factor;
x(8+3)
=11x
#1. B
<span>(z * z^2 + z * 2z + z * 4) – (-2 *z^2 – (-2) 2z – (-2) 4)
Z^3 + 2z^2 + 4z – 2z^2 -4z – 8
Z^3 + 2z^2 – 2z^2 + 4z – 4z – 8
Z^3 - 8
</span>
#2 and #3. D
<span>(x + y)(x + 2)
x^2 + 2x + yx + 2y
</span>
#4. D.
<span>(x - 7)(x + 7)(x- 2)
x^2 + 7x – 7x -49
x^2 + x – 49
x^2 -49
(x^2 – 49 ) (x – 2)
x^3 – 2x^2 – 49x + 98
</span>
#5. C
(y - 4) = 0
y = 4
(x + 3)= 0
x = -3
#6. A and B
