1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Firlakuza [10]
3 years ago
13

What is the slope on this graph PLEASE HELP FAST!!!

Mathematics
2 answers:
TEA [102]3 years ago
8 0

Answer:

slope = 6

Step-by-step explanation:

slope = rise/run

rise = 12 run = 2

Murrr4er [49]3 years ago
3 0

Answer:

SORRY I dont know this one I would help if I could ‍♀️

Step-by-step explanation:

You might be interested in
Assume the readings on thermometers are normally distributed with a mean of 0degreesc and a standard deviation of 1.00degreesc.
Tanzania [10]

Let Z be the reading on thermometer. Z follows Standard Normal distribution with mean μ =0 and standard deviation σ=1

The probability that randomly selected thermometer reads greater than 2.07 is

P(z > 2.07) = 1 -P(z < 2.07)

Using z score table to find probability below z=2.07

P(Z < 2.07) = 0.9808

P(z > 2.07) = 1- 0.9808

P(z > 2.07) = 0.0192

The probability that a randomly selected thermometer reads greater than 2.07 is 0.0192

3 0
3 years ago
I'll give brainliest if u are right ​
emmainna [20.7K]

Answer:

0.3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Can anyone help me out? Steps would be useful but not needed. Its Trig-Missing Sides.
Hitman42 [59]

Answer:

10.3 units

Step-by-step explanation:

Recall: SOHCAHTOA

Reference angle = 69°

Side length Opposite to reference angle = x

Hypotenuse length = 11

Thus, apply the trigonometric ratio, SOH:

Sin 69 = Opp/Hyp

Substitute

Sin 69 = x/11

11 × Sin 69 = x

10.2693847 = x

x = 10.3 units (nearest tenth)

5 0
3 years ago
what is the coordinate of the vertex of the parabola y-2=1/12(x+10) a. ( 10,-2) b. (-10,2) c. (-2,10) d. (2.-10)
solniwko [45]

Answer:

y-a= c(x-b)^2

With the vertex V= (b,a)

We see that b = -10 and a = 2 and then the vertes wuld be:

V= (-10,2)

And the best option is:

b. (-10,2)

Step-by-step explanation:

For this problem we have the following function:

y-2 = \frac{1}{2} (x+10)

And if we compare this expression with the general expression for a parabola given by:

y-a= c(x-b)^2

With the vertex V= (b,a)

We see that b = -10 and a = 2 and then the vertes wuld be:

V= (-10,2)

And the best option is:

b. (-10,2)

4 0
3 years ago
A rectangle with sides measuring x in. and 4x-1 in. has an area of 663in.^2. What are the dimensions of the rectangle?
serious [3.7K]

9514 1404 393

Answer:

  13 in by 51 in

Step-by-step explanation:

The area is the product of the dimensions, so is ...

  663 = x(4x -1)

  4x^2 -x -663 = 0 . . . . . . subtract 663 to put in standard form

Using the quadratic formula, we can find the solutions.

  x = (-(-1) ±√((-1)^2 -4(4)(-663)))/(2(4))

  x = (1 ± √10609)/8 = (1 ±103)/8

Only the positive solution is of any use in this problem, so ...

  x = 104/8 = 13

  4x-1 = 4(13)-1 = 51

The dimensions of the rectangle are 13 inches by 51 inches.

__

I find it easiest to solve these using a graphing calculator.

8 0
3 years ago
Other questions:
  • Given that ∠A≅∠B , Evelia conjectured that ∠A and ∠B are acute angles.
    9·1 answer
  • Write the numerical expression using exponents.
    11·1 answer
  • 4+5+8/2x9=????????????
    11·2 answers
  • Given ΔRWS ≅ ΔTUV, find the values of x and y. <br><br> x = ___<br><br> y = ___
    15·1 answer
  • Someone help me please
    11·1 answer
  • Subtract 1/6a+3 from 1/3a−5 . Please Help Will Give !Brainliest! and Medals!!!!!!
    13·1 answer
  • Pythagorean’s theorem
    15·2 answers
  • When subtracting with negative numbers, change the problem to an<br> problem and
    6·1 answer
  • Hi, I'm struggling on level 2 for
    12·1 answer
  • In convex pentagon $ABCDE$, angles $A$, $B$ and $C$ are congruent and angles $D$ and $E$ are congruent. If the measure of angle
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!