Answer: (30.49 years, 42.31 years)
Step-by-step explanation:
The formula to find the confidence interval is given by :-

, where
= Sample mean
z* = Critical value.
= Population standard deviation.
n= Sample size.
As per given , we have
n= 40
We know that the critical value for 99% confidence interval : z* = 2.576 (By z-table)
A 99 percent confidence interval for µ, the true mean age of guests will be :

∴ a 99 percent confidence interval for µ, the true mean age of guests = (30.49 years, 42.31 years)
Answer:
4 to 1
Step-by-step explanation:
The greatest common factor between 8 and 2 is 2. So 2 will go into 8, 4 times. And 2 will go into 2, 1 time. So simplified the equivalent ratio is 4:1.
<span>Maria tiene 32 kg y javier tiene 51 kg
</span>
(google translate, bad spanish)
Remember to incorporate Bimdas, into you calculation and ensure where the addition and subtraction occur you work from left to right.
where is the rest of the information?