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likoan [24]
3 years ago
14

Write an expression for the perimeter of the triangle shown below:

Mathematics
1 answer:
AveGali [126]3 years ago
6 0

Answer:

The answer is 0.1x-16

Step-by-step explanation:

-3.4x+3x+.5x=0.1x and -25+9 is -16  which is 0.1x-16

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The following 5 questions are based on this information: An economist claims that average weekly food expenditure of households
liq [111]

Answer:

Null hypothesis:\mu_{1}-\mu_{0}\leq 0

Alternative hypothesis:\mu_{1}-\mu_{2}>0

SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705

b) 2.70

t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850

b. 1.85

p_v =P(Z>1.85)=0.032

b. 0.03

a. We can reject H(0) in favor of H(a)

Step-by-step explanation:

Data given and notation

\bar X_{1}=164 represent the mean for the sample 1

\bar X_{2}=159 represent the mean for the sample 2

\sigma_{1}=12.5 represent the population standard deviation for the sample 1

s_{2}=9.25 represent the population standard deviation for the sample B2

n_{1}=35 sample size selected 1

n_{2}=30 sample size selected 2

\alpha=0.05 represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the expenditure of households in City 1 is more than that of households in City 2, the system of hypothesis would be:

Null hypothesis:\mu_{1}-\mu_{0}\leq 0

Alternative hypothesis:\mu_{1}-\mu_{2}>0

We know the population deviations, so for this case is better apply a z test to compare means, and the statistic is given by:

z=\frac{(\bar X_{1}-\bar X_{2})-0}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Standard error

The standard error on this case is given by:

SE=\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}

Replacing the values that we have we got:

SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705

b. 2.70

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850  

P-value

Since is a one side right tailed test the p value would be:

p_v =P(Z>1.85)=0.032

b. 0.03

Conclusion

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis.

a. We can reject H(0) in favor of H(a)

4 0
3 years ago
Helpppppppppppppppppp<br> Pppppo
pantera1 [17]

Answer:

(2 * L)+(2 * W)

Step-by-step explanation:

4 0
3 years ago
What Is The Overall Home Work Score ??
Blababa [14]

Answer:

it is usally an 25%

Step-by-step explanation:

8 0
3 years ago
A gift box is a rectangular prism. The box measures 12 in by 14 in by 7 in.
Olin [163]

Answer:

1176

Step-by-step explanation:

12 times 7 equals 84.84 times 14 is 1176

4 0
3 years ago
Read 2 more answers
The manager of a warehouse would like to know how many errors are made when a product’s serial number is read by a bar-code read
stira [4]
The mean of the answer is 20.5 because you add all of the number together and divide by 6 because there's 6 numbers. 
I'm sorry, but I don't know how to do the standard deviation... 
Hope this helped!
4 0
3 years ago
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