Answer:
4.5 % alloy
Step-by-step explanation:
Let x = amt of 30% alloy
The resulting total is to be 25 oz, therefore:
(25-x) = amt of 5% alloy:
A typical mixture equation:
.30x + .05(25-x) = .20(25)
.30x + 1.25 - .05x = 5 .30x - .05x = 5 - 1.25
.25x = 3.75
x = 3.75%2F.25
x = 15 oz of 30% alloy required
then
25-15 = 10 oz of 5% alloy:
Check solution
.30(15) + .05(10) = .20(25)
4.5 + .5 = 5
To express the height as a function of the volume and the radius, we are going to use the volume formula for a cylinder:

where

is the volume

is the radius

is the height
We know for our problem that the cylindrical can is to contain 500cm^3 when full, so the volume of our cylinder is 500cm^3. In other words:

. We also know that the radius is r cm and height is h cm, so

and

. Lets replace the values in our formula:





Next, we are going to use the formula for the area of a cylinder:

where

is the area

is the radius

is the height
We know from our previous calculation that

, so lets replace that value in our area formula:



By the commutative property of addition, we can conclude that:
Answer:
no
Step-by-step explanation:
if it was a factor then, 2-3x = 0
x= 2/3
putting x = 2/3 in eqn,
(2/3)^2 - 2/3 +1 =7/9....so it is not a factor
Answer:
47.32 kilometers per hour
Step-by-step explanation:
194 (kilometers) / 4.1 ( hours)
194/4.1 = 47.32 kilometers per hour.
Answer:
18/10
Step-by-step explanation: