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Bingel [31]
3 years ago
8

Question 4: Factor (2x^2 + 4x) (x^2 + x - 6) completely.

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
7 0

Answer:

2x(x+2) (x-2) (x+3)

Step-by-step explanation:

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True or false: if m=11, then 12m - 16 = 112
alexandr402 [8]
false, the real answer is 116
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3 years ago
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Three ingredients A, B, and C are mixed by weight in the ratio of 1:2:3 respectively to make a mixture. How many pounds of ingre
cluponka [151]

Answer:

B. 24

Step-by-step explanation:

just took the quiz and got it right

8 0
3 years ago
Find the slope of the line through the given points.(-4,7) and (-1,-3)Is the slope increasing or decreasing?
galina1969 [7]

• The following formula can be used to find the slope of a line:

m=\frac{y_2-y_1}{x_2-x_1}

These points are on the line:

(x_1,y_1);(x_2,y_2)

Given the following points:

\mleft(-4,7\mright);(-1,-3)

Then, you can set up that:

\begin{gathered} y_2=-3_{} \\ y_1=7 \\ x_2=-1 \\ x_1=-4 \end{gathered}

Therefore, substituting values into the formula and evaluating, you get:

\begin{gathered} m=\frac{-3-7}{-1-(-4)} \\  \\ m=\frac{-10}{-1+4} \\  \\ m=-\frac{10}{3} \end{gathered}

• As you can notice, the slope is negative. Therefore, you can determine that it is decreasing.

Therefore, the answers are:

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m=-\frac{10}{3}

• It is decreasing.

4 0
1 year ago
Help me please I don’t know this
Afina-wow [57]
The answer is the number will have to be less than 11 which means that it is a. 9
sorry if it is incorrect.
8 0
3 years ago
The equation for the motion of an object with constant acceleration is d=vt+0.5at² where d is distance traveled in ft, v is star
sasho [114]

The expression for the distance the car travels after t seconds is d = 200t + 50t²

<h3>Equation of motion </h3>

From the question, we are to write an expression for the distance the car travels after t seconds

From the given information,

The equation for the motion of an object with constant acceleration is

d = vt + 0.5at²

For the race car,

v = 200 ft/s

a = 100 ft/s²

Putting the parameters into the equation, we get

d = 200t + 0.5(100)t²

d = 200t + 0.5 ×100)t²

d = 200t + 50t²

Hence, the expression for the distance the car travels after t seconds is d = 200t + 50t²

Learn more on Equations of motion here: brainly.com/question/20910641

#SPJ1

3 0
2 years ago
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