Question 4: Factor (2x^2 + 4x) (x^2 + x - 6) completely.

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

7 0

Answer:

2x(x+2) (x-2) (x+3)

Step-by-step explanation:

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Bradley and Kelly are out flying kites at a park one afternoon. A model of Bradley and Kelly's kites are shown below on the coor

Alex787 [66]

The correct answer is:

C. They are similar because the corresponding sides of kites KELY and BRAD all have the relationship 2:1.

Using the distance formula,

$d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

the lengths of the sides of BRAD are:

$\text{BR}=\sqrt{(7-6)^2+(3-4)^2}=\sqrt{1^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}\\\\\text{RA}=\sqrt{(6-3)^2+(4-3)^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{AD}=\sqrt{(3-6)^2+(3-2)^2}=\sqrt{(-3)^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{DB}=\sqrt{(6-7)^2+(2-3)^2}=\sqrt{(-1)^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}$

The lengths of the sides of KELY are:

$\text{KE}=\sqrt{(2-0)^2+(11-9)^2}=\sqrt{2^2+2^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\\\\\text{EL}=\sqrt{(0-2)^2+(9-3)^2}=\sqrt{(-2)^2+6^2}=\sqrt{40}=2\sqrt{10}\\\\\text{LY}=\sqrt{(2-4)^2+(3-9)^2}=\sqrt{(-2)^2+(-6)^2}=\sqrt{40}=2\sqrt{10}\\\\\text{YK}=\sqrt{(4-2)^2+(9-11)^2}=\sqrt{2^2+(-2)^2}=\sqrt{8}=2\sqrt{2}$

Each side of KELY is twice the length of the corresponding side on BRAD. This makes the ratio of the sides 2:1 and the figures are similar.

8 0

3 years ago

Read 2 more answers

Calculate the perimeter of this figure.Round your answer to the nearest tenth.p=(?)ft 8,10,8.9,4

o-na [289]

Answer:

30.9

Step-by-step explanation:

8 + 10 + 8.9 + 4 = 30.9

5 0

2 years ago

A parabola can be drawn given a focus of (-4,10) and a directrix of y=-4 write the equation of the parabola in any form

sweet-ann [11.9K]

Answer:

$(x+4)^2=28(y-3)$

Step-by-step explanation:

The directrix of the parabola is the horizontal line with the eqaution $y=-4.$ The focus of the parabola is at point (-4,10), than the axis of symmetry of the parabola is the perpendicular line to the directrix passing through the focus. Its equation is $x=-4$

The distance between the directrix and the focus is $|10-(-4)|=14,$ so $p=14$ and the vertex is at point $\left(-4,10-\dfrac{14}{2}\right)\rightarrow (-4,3)$