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Elis [28]
3 years ago
13

The equation y−5=−2(x−3) is in point-slope form. Which shows this equation in slope-intercept form?

Mathematics
1 answer:
MAXImum [283]3 years ago
4 0

y - 5 = -2(x - 3)

Distribute -2.


y - 5 = -2x + 6

Add 5 to both sides.


y = -2x + 11

B) y = -2x + 11

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3 years ago
Read 2 more answers
Please answer, thank you
cupoosta [38]

Answer:

Step-by-step explanation:

Since y = -3 we can plug straight into the other equation

--> -x + 2y = -6

-x + 2(-3) = -6

-x - 6 = -6

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x = 0

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4 0
3 years ago
The graph of a quadratic function f(x) intersects the x-axis At -3 and 5. Create a function that would produce these results.
FinnZ [79.3K]

Answer:

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Step-by-step explanation:

∵ The function intersect x-axis at -3 and 5

∴ f(x) = 0 at x = -3 , 5

∵ The form of the quadratic equation is ⇒ ax² + -b/a x + c/a = 0

                                                                       ax² - b/a x + c/a = 0

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∴ b = -3 + 5 = 2

∴ c = -3 × 5 = -15

∴ f(x) = x² - 2x - 15

6 0
3 years ago
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