Which combination of integers can be used to generate the Pythagorean triple (7,24,25)?

Mathematics

2 answers:

lilavasa [31]4 years ago

5 0

it would be b...........

allochka39001 [22]4 years ago

3 0

A Pythagorean triple is a set of thre integer numbers, a, b and c that meet the Pythgorean theorem a^2 + b^2 = c^2

Use Euclide's formula for generating Pythagorean triples.

This formula states that given two arbitrary different integers, x and y, both greater than zero, then the following numbers a, b, c form a Pythagorean triple:

a = x^2 - y^2

b = 2xy

c = x^2 + y^2.

From a = x^2 - y^2, you need that x > y, then you can discard options A and D.

Now you have to probe the other options.

Start with option B, x = 4, y = 3

a = x^2 - y^2 = 4^2 - 3^2 = 16 -9 = 7

b = 2xy = 2(4)(3) = 24

c = x^2 9 y^2 = 4^2 + 3^2 = 16 + 9 = 25

Then we could generate the Pythagorean triple (7, 24, 25) with x = 4 and y =3.

If you want, you can check that a^2 + b^2 = c^2; i.e. 7^2 + 24^2 = 25^2

The answer is the option B. x = 4, y = 3

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3. Write an equation in point-slope form for the line through the given point with the given slope.

jok3333 [9.3K]

Answer:

Step-by-step explanation:

recall that point-slope form of a linear equation is expressed as follows

y - y1 = m (x - x1)

where m = slope and (x1, y1) is the coordinate of any point on the line

so, here we have m = (3/5), x1 = 4 and y1 = -6

substitute these into the formula

y - (-6) = (3/5) (x - 4)

y + 6 = (3/5) (x - 4)----> answer

5 0

4 years ago

Read 2 more answers

Community college students conduct a survey at their college. They ask "Do you plan to transfer to a university to pursue a bacc

Tamiku [17]

Answer:

$0.8 - 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.697$

$0.8 + 2.58\sqrt{\frac{0.8(1-0.8)}{100}}=0.903$

The 99% confidence interval would be given by (0.697;0.903)

And the best option is : 0.697 to 0.903

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case the conditions we have the conditions to assume a normal distribution for the population proportion since:

np=100*0.8=80 >10 , n(1-p) = 10*(1-0.8) =20 >10

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by $\alpha=1-0.99=0.01$ and $\alpha/2 =0.005$ . And the critical value would be given by: