The area of a regular hexagon is
... A = (3√3)/2×s² . . . . . where s is the side length
Of course, the 6-sided figure will have a side length that is 1/6 of the perimeter.
... s = (48 in)/6 = 8 in
... A = (3√3)/2×(8 in)² = 96√3 in² . . . area of your regular hexagon
Answer:
attempt it, if it's too hard, sleep
that's what I would do lol
Step-by-step explanation:
Answer:
quadrilateral
Step-by-step explanation:
Answer:
<em>angle ABD =</em><u><em>55 degree</em></u>
<em>angle BCD= </em><u><em>125 degree</em></u>
Step-by-step explanation:
angle ABD and angle DBC are supplementary angles.
Hence, angle ABD +angle DBC = 180 --equation 1
angle ABD = (2x+15) ---equation 2
angle BCD = (4x+45) ------equation 3
ABD+DBC=180
(2x+15) + ( 4x+45 ) = 180
2x+4x+15+45=180
6x+60=180
6x=180-60
6x=120
x=120/6=20
angle ABD= 2x+15= 2(20) +15
=40+15= 55 degree
angle BCD= 4x+45 = 4(20) +45
= 80+45= 125 degree
Hence, angle ABD =55 degree
angle BCD= 125 degree
<em>Hope this helps.</em>
Answer:
300
Step-by-step explanation: