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2 years ago

What equation can be written as...???

Mathematics

1 answer:

Mariulka [41]2 years ago

5 0

Answer:

Step-by-step explanation:

$\sqrt{x+4}=x$

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You notice a hot air balloon descending. The elevation h

ANEK [815]

Answer:

the domain is 0 x 45 and the range is 0 h 360. The slope is -8, so the change in the height of the ballon is -8 feet per second. The h-intercept is 360, so the height of the ballon when the first noticed it was 360 feet. The x-intercept is 45, so the time it took the hot air balloon to reach the ground was 45 seconds.

Step-by-step explanation:

8 0

3 years ago

What is what is 2000 * 3000

elena-14-01-66 [18.8K]

Answer:

600,000

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

16) Please help with question. WILL MARK BRAINLIEST + 10 POINTS.

Katyanochek1 [597]

We will use the sine and cosine of the sum of two angles, the sine and consine of $\frac{\pi}{2}$ , and the relation of the tangent with the sine and cosine:

$\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta

\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta$

$\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0$

$\tan\alpha = \dfrac{\sin\alpha}{\cos\alpha}$

If you use those identities, for $\alpha=x,\ \beta=\dfrac{\pi}{2}$ , you get:

$\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x$

$\cos\left(x+\dfrac{\pi}{2}\right) = \cos x \cdot \cos\dfrac{\pi}{2} - \sin x\cdot\sin\dfrac{\pi}{2} = \cos x \cdot 0 - \sin x \cdot 1 = -\sin x$

Hence:

$\tan \left(x+\dfrac{\pi}{2}\right) = \dfrac{\sin\left(x+\dfrac{\pi}{2}\right)}{\cos\left(x+\dfrac{\pi}{2}\right)} = \dfrac{\cos x}{-\sin x} = -\cot x$

3 0

3 years ago

Which statements are true? (look at picture)

Makovka662 [10]

Answer:

D is true, E is true, F is true

Step-by-step explanation:

Hello,

n is an odd number it means that n = 2a+1 where a is integer

$n^2-1=(2a+1)^2-1=4a^2+4a+1-1=4a(a+1)$

this is not an odd number

$n(n-1)=(2a+1)2a$

this is not an odd number

$(n-1)^2=(2a+1-1)^2=4a^2$

this is not an odd number

$n^2+2=(2a+1)^2+2=4a^2+4a+1+2=4a^2+4a+3= 2(2a^2+2a+1)+1$

so this is an odd number

$n(n-2)=(2a+1)(2a-1)=4a^2-1=4a^2-2+1=2(2a^2-1)+1$

so this is an odd number

$(n-2)^2=(2a+1-2)^2=(2a-1)^2=4a^2-4a+1 = 2(2a^2-2a)+1$

this is an odd number

hope this helps

7 0

3 years ago

Help please Please help

ElenaW [278]

9514 1404 393

Answer:

4. True

5. False

Step-by-step explanation:

4. The number of x-intercepts produced by the quadratic formula may be 0, 1, or 2. It will be 0 if the two roots are complex. It will be 1 if the two roots lie in the same place (one root with multiplicity 2). It is true that there may be only one x-intercept.

5. The value of 'b' in the quadratic formula is the coefficient of the linear term. In the given quadratic, it is -5, not 5.

8 0

2 years ago