PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!

Which correctly names the line in this figure? A.A B.HG C.F D.FGH

MAVERICK [17]

B

Two points is a line
One capital letter is the plane

4 0

3 years ago

An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of

ANEK [815]

Answer:

(a) 0.152

(b) 0.789

(c) 0.906

Step-by-step explanation:

Let's denote the events as follows:

F = The word free occurs in an email

S = The email is spam

V = The email is valid.

The information provided to us are:

The probability of the word free occurring in a spam message is, $P(F|S)=0.60$
The probability of the word free occurring in a valid message is, $P(F|V)=0.04$
The probability of spam messages is,

$P(S)=0.20$

First let's compute the probability of valid messages:

$P (V) = 1 - P(S)\\=1-0.20\\=0.80$

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

$P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The probability that a message contains the word free is:

$P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\$

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

The probability that a message is spam provided that it contains free is:

$P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\$

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

The probability that a message is valid provided that it does not contain free is:

$P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566$

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0

3 years ago

Victor made a cake for his cousin's birthday party. Victor baked the cake for 40 minutes. It took 8 times as long for Victor to

irga5000 [103]

Answer:

320 min. or 5 hrs 20 min.

Step-by-step explanation:

40 x 8 = 320

6 0

3 years ago

What is the answer X/7-3>8

mamaluj [8]

Answer:

x > 77

Step-by-step explanation:

According to order of operations rules, we must carry out division before addition or subtraction. In this case we wish to isolate x and are permitted to simplify the inequality by combining the "like terms" 3 and 8, as follows:

X/7-3>8

+3 +3

--------------

x/7 > 11

The easiest way in which to solve for x is to multiply both sides of this inequality by 7:

7(x/7) > 7(11), or

x > 77

All numbers greater than 77 are part of the solution set.

4 0

3 years ago

PLEASE I NEED COORDINATES!!! What is the solution of the system? Use the elimination method. 2x+y=206x−5y=12 Enter your answer i

Butoxors [25]

the answer of 2x +y = 20 ; 6x -5y =12

{ explained in image}

8 0

3 years ago