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3 years ago

PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!

Mathematics

1 answer:

nalin [4]3 years ago

4 0

The answer is: cosV=39/89=0,43

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The expression (x-6)2is equivalent to

Marizza181 [45]

(x - 6) * 2

I'm assuming this is the expression that you typed out, if it isn't, please let me know in the comments :)

Use the distributive property:

= 2(x) - 2(6)

Multiply and simplify

= 2x - 12

This should be the expression that is equivalent to the original. Let me know if you need any clarifications, thanks!

5 0

3 years ago

I need help. line wx is parallel to line yz

Oksana_A [137]

Answer:

Step-by-step explanation:

<ABY=<ZBY(VERTICAL ANGLES)

SO.

3x-5=2x+40

3x-2x=40+5

x=45

3 0

3 years ago

Read 2 more answers

What is 2(9)0-7+3 to the 3rd power

RSB [31]

Answer:

I got -64

Step-by-step explanation:

The begging multiplication is 0 and subtract -7 is becomes just -7 then add 3 and it is -4 to the third power is -64

8 0

3 years ago

Who had this before if so can I get help

telo118 [61]

2*3+4=10

5+2x2=9

4-3+2=3

4*3+2=14

20-4x3+6=14

16-30/2+11=12

24/6*5=20

15/5+2=5

2+2*9-5=15

12-3+4*2=1

12/3+3*4=16

9-6/3=7

16-3*4=4

36/4/9=1

The last one is yours

6 0

3 years ago

What is the result of a dilation of scale factor 3 centered at the origin of the line 2y + 3x=10?? PLEASE HELP PLEASEEEEEEEEE

maks197457 [2]

Given:

The equation of a line is:

$2y+3x=10$

The line is dilated by factor 3.

To find:

The result of dilation.

Solution:

The equation of a line is:

$2y+3x=10$

For $x=0$ ,

$2y+3(0)=10$

$2y+0=10$

$y=\dfrac{10}{2}$

$y=5$

For $x=2$ ,

$2y+3(2)=10$

$2y+6=10$

$2y=10-6$

$2y=4$

Divide both sides by 2.

$y=\dfrac{4}{2}$

$y=2$

The given line passes through the two points A(0,5) and B(2,2).

If the line dilated by factor 3 with origin as center of dilation, then

$(x,y)\to (3x,3y)$

Using this rule, we get

$A(0,5)\to A'(3(0),3(5))$

$A(0,5)\to A'(0,15)$

Similarly,

$B(2,2)\to B'(3(2),3(2))$

$B(2,2)\to B'(6,6)$

The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-15=\dfrac{6-15}{6-0}(x-0)$

$y-15=\dfrac{-9}{6}(x)$

$y-15=\dfrac{-3}{2}x$

Multiply both sides by 2.

$2(y-15)=-3x$

$2y-30=-3x$

$2y+3x=30$

Therefore, the equation of the line after the dilation is $2y+3x=30$ .

3 0

3 years ago