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Ymorist [56]
3 years ago
8

The perimeter of a patio is 64 feet. The width of the patio is 12 feet and the length of the patio is (x+6) feet. What is the le

ngth of the patio?
Mathematics
1 answer:
Ludmilka [50]3 years ago
6 0

Here's how you do it!

12+12+x+6+x+6=64

36+2x=64

2x=28

x=14

The length is 14 feet!

You might be interested in
A fruit company delivers its fruit in two types of boxes: large and small. A delivery of 5 large boxes and 6 small boxes has a t
Olin [163]

Answer:

  • large: 18.5 kg
  • small: 15.75 kg

Step-by-step explanation:

Let b and s represent the weights of the big and small boxes, respectively. Then the two delivered weights can be summarized as ...

  5b +6s = 187

  3b +2s = 87

We can eliminate the "s" variable by subtracting the first equation from 3 times the second:

  3(3b +2s) -(5b +6s) = 3(87) -(187)

  4b = 74 . . . . . collect terms

  b = 18.5 . . . . . divide by 4

Using this value in the second equation, we find ...

  3(18.5) +2s = 87

  2s = 31.5 . . . . . . . . subtract 55.5

  s = 15.75 . . . . . . . . divide by 2

The large box weighs 18.5 kg; the small box weighs 15.75 kg.

5 0
3 years ago
Andrew is showing his work in simplifying (−5.7 + 2.2) − 1.1.
Leviafan [203]
Answer: In step 1, Andrew used the commutative property

Explanation:
In step 1 he used commutative, which is a + b = b + a
(- 5.7 + 2.2) = 2.2 + (- 5.7)

Step 2, he used associative property, not the distributive.

Step 3, he just added5.7 + 1.1 = 6.8

Step 4, he distributed the negative sign:
- (6.8) = - 6.8
6 0
3 years ago
Read 2 more answers
If you know that​ R' (20)=50 and​ R''(20)=-4, approximate​ R'(24)
vladimir1956 [14]

Approximate <em>R'</em> by using a linear approximation: for <em>x</em> close enough to 24, you have

<em>R'(x)</em> ≈ <em>L(x)</em> = <em>R' </em>(20) + <em>R''</em> (20) (<em>x</em> - 20)

Then

<em>R'</em> (24) ≈ <em>R'</em> (20) + <em>R''</em> (20) (24 - 20) = -4 + 50 (24 - 20) = 196

4 0
2 years ago
The difference of the range and the interquartile range of the data set represented by the box plot is
Varvara68 [4.7K]

Answer:

R - IQR = 10

Step-by-step explanation:

The interquartile range is IQR is:

IQR = Q_3 -Q_1

Where:

Q_3 = third quartile

Q_1 = first quartile

So the interquartile range is the difference between the highest quartile and the lowest quartile. In other words, it is the width of the box in the diagram.

So:

IQR = 29 -21\\IQR = 8

The R range is the difference between the highest value and the lowest. In other words:R = 34 -16\\R = 18

Finally:

R - IQR = 18 - 8 = 10

5 0
3 years ago
Read 2 more answers
In the year 2005, a total of 750 fish were introduced into a man made lake. The fish population was expected to grow at a rate o
Butoxors [25]

Answer:

In 2050 fish population is 27000

Step-by-step explanation:

Exponential change can be modeled by,

F=F(0)+x^{n}

Where F(0) is the initial value of 750, x is the rate of change. It is greater then 1 when there is growth and less then 1 when there is decay. and n is the number of time periods.

The rate of change in percentage is 8.3%

That means, after 1 year fish will become 108.3 for 100 fish.

Then x=\frac{108.3}{100}

x=1.083

Difference of years is, n=2050-2005=45

Then, F=750+1.083^{45}

F=27000

So, the fish population in 2050 is 27000

3 0
3 years ago
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