Answer: none
Step-by-step explanation:
(A)
(16÷32/10) ×2 + 0.2×(90)
Using bodmas principle ; solve bracket
(16×10/32)×2 + (2/10×90)
10+18 =28
(B)
{(16÷32/10) × (2+2/10)} ×90
Open brackets
{(16×10/32) × (22/10)} ×90
(5×11/5) ×90
11×90 = 990
(C)
16÷{(32/10×2) + (2/10×8)} +82
Open brackets, solve division first, dolled by addition
16÷(32/5 + 8/5) +82
16÷(40/5) +82
16÷8 +82
2+82= 84
(D)
[16÷(32/10 ×2) + 0.2× (90)]
16÷ (32/5) + 2/10 ×90
Solve division
16×5/32 + 18
5/2 + 18
L.c.m of denominator (2&1) =2
(5+36) / 2 = 41/2
=20.5
It depends on the terms of the account.
If interest is compounded annually, 650*1.06^5 ≈ 869.85 . . . . dollars.
If interest is compounded quarterly, 650*1.015^20 ≈ 875.46 . . dollars.
If interest is compounded monthly, 650*1.005^60 ≈ 876.75 . . .dollars.
First add the number of total larges ordered 22+5=27 then divide 22/27=.814 to make the answer a percent times by 100. .814x100=81.5% to double check you can multiply .814 by number of larges and should get number of hot larges ordered. .814x27=22
That point of concurrency is called the incenter of the triangle
