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3 years ago

How does reflection change a figure?

Mathematics

2 answers:

Elanso [62]3 years ago

8 0

Answer:

reflection changes a figure by:

Step-by-step explanation:

for example when you have a plot like (2,6) you have to plot the 2 on the y axis and the 6 on the x axis. when you do that you have the original graph. but then when you reflect a figure it has a negative plot instead but the same coordinates. hope this was helpful in some way!

bija089 [108]3 years ago

3 0

Answer:

The reflection changes the orientation of a figure by flipping it to the other side

explanation:

Think of a mirror it reflects your physical image

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WHAT IS THE TRUE STATMENTS

PtichkaEL [24]

Answer:

number 3

Step-by-step explanation:

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2 years ago

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Jose needs to enclose a rectangular section of his yard. The perimeter of the section is 27 feet, and the area is 35 square foot

Ratling [72]

A = 35 sq ft
L = 10 ft 
W = 3.5 ft

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3 years ago

Write the equation of the line given an x -intercept of 10 and y -intercept of 5.

Sergeu [11.5K]

Answer:

y = (-1/2)x + 5

Step-by-step explanation:

As we move from the y-intercept (0, 5) to the x-intercept (10,0), x increases by 10 units while y decreases by 5 units. Thus, the slope of this line is

m = rise / run = -5 / 10 = -1/2.

Since we know both the slope and the y-intercept of this line, let's use the slope-intercept form of the equation of a straight line: y = mx + b.

Substituting -1/2 for m and 5 for b, we get:

y = (-1/2)x + 5

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4 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

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3 years ago

F(n)=4n g(n)=n2+2n find f(g(-6))

ELEN [110]

Answer:

When f(n) = 4n and g(n) = n² + 2n, f(g(-6)) = 96.

Step-by-step explanation:

To evaluate f(g(-6)), first find g(-6).

g(n) = n² + 2n

Substitute value.

g(-6) = (-6)² + 2(-6)

Square -6. Remember that (-x)² = x²

g(-6) = 36 + 2(-6)

Multiply 2 and -6.

g(-6) = 36 - 12

Subtract 12 from 36.

g(-6) = 24.

Now knowing this, substitute that value into f(n).

f(g(-6)) = f(24)

f(n) = 4n

Substitute value.

f(24) = 4(24)

Multiply 4 and 24.

f(24) = 96.

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3 years ago