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3 years ago

Situation 1: Two students, Theo and Lance, each have some chocolates. They know that

Mathematics

1 answer:

vivado [14]3 years ago

4 0

They each have two chocolates so those numbers of chocolates are the same.

Not counting the tubs, Arthur has one bag of chocolates and 25 loose chocolates; Oliver has two bags and 7 loose. If they both have the same total number of chocolates, then the difference in the number of loose chocolates they have (25-7=18) must be the number of chocolates in a bag.

There is no information given, in the problem as you show it, that allows us to determine the number of chocolates in a tub.

Answers: chocolates in a bag: 18. chocolates in a tub: unknown.

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A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard d

bagirrra123 [75]

The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C: [130.10, 143.90]

<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

Sample size n > 30
Sample mean = $\overline{x}$
Sample standard deviation = s
Population standard deviation = $\sigma$
Level of significance = $\alpha$

Then the confidence interval is obtained as

Case 1: Population standard deviation is known

$\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}$

Case 2: Population standard deviation is unknown.

$\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}$

For this case, we're given that:

Sample size n = 90 > 30
Sample mean = $\overline{x}$ = 138
Sample standard deviation = s = 34
Level of significance = $\alpha$ = 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).

At this level of significance, the critical value of Z is: $Z_{0.1/2}$ = ±1.645

Thus, we get:

$CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]$

Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C: [130.10, 143.90]

Learn more about confidence interval for population mean from large samples here:

brainly.com/question/13770164

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1 year ago

A 12" pizza costs $14. What is the<br> price per square inch?

timama [110]

Answer:

0.857$ (Its really big in answer but This is the average result.

The REAL answer

0.857142857$

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2 years ago

100 points, please help? its my last question im stuck on and im almost done! explanations are appreciated too (i wont forget to

lapo4ka [179]

First box’s is angle addition postulate. The the second box is x=15

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3 years ago

Read 2 more answers

What's the answer to the question?

Tom [10]

The king of hearts in cards

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2 years ago

Which statement is true about the graphed function?

frutty [35]

The true statement, regarding the signal of the graphed function, is given by:

F(x) > 0 over the interval (–∞, –4).

<h3>When a function is positive and when it is negative?</h3>

Looking at it's graph, we have that:

The function is positive when it is above the x-axis.

The function is negative when it is below the x-axis.

Researching this problem on the internet and looking at the graph of the function, the function is negative for <u>all values to the right of x = -4</u>, and positive to the left, hence the correct statement is given by:

F(x) > 0 over the interval (–∞, –4).

More can be learned about the signal of a function at brainly.com/question/25638609

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1 year ago