Situation 1: Two students, Theo and Lance, each have some chocolates. They know that

Mathematics

1 answer:

vivado [14]3 years ago

4 0

They each have two chocolates so those numbers of chocolates are the same.

Not counting the tubs, Arthur has one bag of chocolates and 25 loose chocolates; Oliver has two bags and 7 loose. If they both have the same total number of chocolates, then the difference in the number of loose chocolates they have (25-7=18) must be the number of chocolates in a bag.

There is no information given, in the problem as you show it, that allows us to determine the number of chocolates in a tub.

Answers: chocolates in a bag: 18. chocolates in a tub: unknown.

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If a/\2+1/a/\2=11, then a+1/a=?

Nadya [2.5K]

Answer:

$\pm \sqrt{13}$

Step-by-step explanation:

$\bigg(a + \frac{1}{a} \bigg)^{2} = {a}^{2} + \frac{1}{ {a}^{2} } + 2 \times a \times \frac{1}{a} \\ \\ \bigg(a + \frac{1}{a} \bigg)^{2} = 11 + 2 \\ \\ \bigg(a + \frac{1}{a} \bigg)^{2} = 13 \\ \\ \bigg(a + \frac{1}{a} \bigg) = \pm \sqrt{13}$