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Artist 52 [7]
3 years ago
15

Find the smallest 4 digit number that can be formed with the digits 0,4, 2 and 6​

Mathematics
1 answer:
Dovator [93]3 years ago
4 0

Answer:

dgjkgc!vhlyj do gjgmnnnhchvgjffjhvhfkjufug

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Been stuck on this one for a while will give brainiest plus this question is worth 20 points im desperate
bulgar [2K]

Answer:

the scale factor is 25, 3000/125 scaled down,

Step-by-step explanation:

you can also explain this with a 25:1 ratio, 25 inches from the original scaled to 1 inch for the photo copy.

7 0
2 years ago
What is 5/16 divided by 2/3
gayaneshka [121]
You take 5/16 division you change it in matplication 3 goes up and 2 comes down so you numbers will be
5/16 times 3/2 you take 5 time3 is 15 and 16 times 2 is 32
So ur answer will be 15/32
8 0
3 years ago
What is the area of the regular polygon?
BartSMP [9]

Answer:

You could use the polygon area formula OR here's an easier solution

We draw the lines DC and DE

Angle ADC = 120°

Triangle ADC is a 30 60 90 triangle

In such a triangle Line AE = hypotenuse * sq root (3) /2

Line AE = 3 * 0.8660254038  = 2.5980762114

Line DE = 1.5

Area of Triangle ADE = .5 * 1.5 * 2.5980762114 =

1.9485571586   square meters and entire area of Triangle

ABC = 6 * 1.9485571586

which equals 11.6913429513  square meters

Step-by-step explanation:

6 0
3 years ago
15 more than half a number is 9
avanturin [10]
1/2n + 15 = 9 <== ur equation
1/2n = 9 - 15
1/2n = - 6
n = -6 * 2
n = - 12 <== ur solution
4 0
3 years ago
A company manufactures running shoes and basketball shoes. The total revenue (in thousands of dollars) from x1 units of running
Alborosie

Answer:

x_1 =2 , x_2=7

Step-by-step explanation:

Consider the revenue function given by R(x_1,x_2) = -5x_1^2-8x_2^2 -2x_1x_2+34x_1+116x_2. We want to find the values of each of the variables such that the gradient( i.e the first partial derivatives of the function) is 0. Then, we have the following (the explicit calculations of both derivatives are omitted).

\frac{dR}{dx_1} = -10x_1-2x_2+34 =0

\frac{dR}{dx_2} = -16x_2-2x_1+116 =0

From the first equation, we get, x_2 = \frac{-10x_1+34}{2}.If we replace that in the second equation, we get

-16\frac{-10x_1+34}{2} -2x_1+116=0= 80x_1-2x_1+116-272= 78x_1-156

From where we get that x_1 = \frac{156}{78}=2. If we replace that in the first equation, we get

x_2 = \frac{-10\cdot 2 +34}{2}=\frac{14}{2} = 7

So, the critical point is (x_1,x_2) = (2,7). We must check that it is a maximum. To do so, we will use the Hessian criteria. To do so, we must calculate the second derivatives and the crossed derivatives  and check if the criteria is fulfilled in order for it to be a maximum. We get that

\frac{d^2R}{dx_1dx_2}= -2 = \frac{d^2R}{dx_2dx_1}

\frac{d^2R}{dx_{1}^2}=-10, \frac{d^2R}{dx_{2}^2}=-16

We have the following matrix,  

\left[\begin{matrix} -10 & -2 \\ -2 & -16\end{matrix}\right].

Recall that the Hessian criteria says that, for the point to be a maximum, the determinant of the whole matrix should be positive and the element of the matrix that is in the upper left corner should be negative. Note that the determinant of the matrix is (-10)\cdot (-16) - (-2)(-2) = 156>0 and that -10<0. Hence, the criteria is fulfilled and the critical point is a maximum

8 0
3 years ago
Read 2 more answers
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