The first thing we must do in this case is to solve both inequations.
We have then:
Inequality 1:
6 -2x <12
6-12 <2x
-6 <2x
-6/2 <x
-3 <x
Inequality 2:
7 + 2x <-11
2x <-11-7
2x <-18
x <-18/2
x <-9
Answer:
(-inf, -9) U (-3, inf)
Answer:
a man owe a debt of 99 naira
naira pays = monthly installments =2.50
how many years would take him to finish the paying the debit
5years
Answer:
Yes, 3 is a primitive root of 7.
Step-by-step explanation:
By definition if primitive root, b is a primitive root of p, where p is a prime, if powers of b includes all residue classes mod p. Here,
mod 7=1
mod 7=3
mod 7=2
mod 7=6
mod 7=4
mod 7=5
And 
=numbers less than 7 and prime to 7=1,2,3,4,5,6, presents in the residue class of 3 mod 7, this proves 3 is a primitive root of 7.
Does it really? Wow. There is no attatchment.
