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leva [86]
3 years ago
8

Let f(x)=6xf(x)=6x. The graph of f(x)f(x) is transformed into the graph of g(x)g(x) by a vertical compression of 1/3 and a trans

lation of 2 units up.
What is an equation for g(x)g(x)?
Mathematics
2 answers:
ANTONII [103]3 years ago
6 0

given: f(x)=6x

transformations: vertical compression of 1/3, translation of 2 units up.

g(x) = 1/3 f (x)

remember: f(x) = 6x

6/3 = 2

so, g(x) = 2(x)

now add 2 since you are transitioning up

your answer is: g(x) = 2(x)+2

(ik this is an old question, but I wanted to ad a clearer explination for ppl that still need help)

elena-s [515]3 years ago
3 0
Vertical compression implies that you multiply the function by a scalar or constant.
---> (1/3)*f(x)

Translating up means you are adding to the y-value or shifting the graph up.
----> f(x) + 2

Put it together and you get:
g(x) =  \frac{1}{3}f(x) + 2
Now replace f(x) with 6x
g(x) = \frac{1}{3} (6x) + 2 = 2x + 2
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A selective university advertises that 96% of its bachelor’s degree graduates have, on graduation day, a professional job offer
OLEGan [10]

Answer:

The probability is  P( p <  0.9207) = 0.0012556

Step-by-step explanation:

From the question we are told

  The population proportion is p = 0.96

 The sample size is  n  =  227

 The number of graduate who had job is  k = 209

Generally given that the sample size is large enough  (i.e n >  30) then the mean of this sampling distribution is  

       \mu_x = p = 0.96

Generally the standard deviation of this sampling distribution is  

    \sigma  = \sqrt{\frac{p (1 - p )}{n} }

=>  \sigma  = \sqrt{\frac{0.96 (1 - 0.96 )}{227} }

=>  \sigma  = 0.0130

Generally the sample proportion is mathematically represented as

      \^ p =  \frac{k}{n}

=> \^ p =  \frac{209}{227}

=> \^ p =  0.9207

Generally probability of obtaining a sample proportion as low as or lower than this, if the university’s claim is true, is mathematically represented as

     P( p <  0.9207) = P( \frac{\^ p - p }{\sigma } <  \frac{0.9207 - 0.96}{0.0130 }  )

\frac{\^ p - p}{\sigma }  =  Z (The  \ standardized \  value\  of  \ \^ p )

   P( p <  0.9207) = P(Z< -3.022 )

From the z table  the area under the normal curve to the left corresponding to    -3.022  is

     P(Z< -3.022 ) = 0.0012556

=> P( p <  0.9207) = 0.0012556

6 0
3 years ago
In AOPQ, o = 700 cm, p = 840 cm and q=620 cm. Find the measure of _P to the<br> nearest degree
Westkost [7]

Given:

In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.

To find:

The measure of angle P.

Solution:

According to the Law of Cosines:

\cos A=\dfrac{b^2+c^2-a^2}{2bc}

Using Law of Cosines in triangle OPQ, we get

\cos P=\dfrac{o^2+q^2-p^2}{2oq}

\cos P=\dfrac{(700)^2+(620)^2-(840)^2}{2(700)(620)}

\cos P=\dfrac{490000+384400-705600}{868000}

\cos P=\dfrac{168800}{868000}

On further simplification, we get

\cos P=0.19447

P=\cos^{-1}(0.19447)

P=78.786236

P\approx 79

Therefore, the measure of angle P is 79 degrees.

8 0
3 years ago
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I need the answer for this
Svetach [21]

Answer:

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Step-by-step explanation:

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adelina 88 [10]
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3 years ago
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AysviL [449]

Answer: 5 (8-9x)

Step-by-step explanation:

25 x 2 - 45 x -10

50 - 45 x -10

40 - 45x

8 0
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