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MaRussiya [10]
3 years ago
14

Which of the following describes the polynomial function?

Mathematics
1 answer:
expeople1 [14]3 years ago
8 0

Answer:

can you put an illustration or picture for me to understand what your saying?.

Step-by-step explanation:

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5
alukav5142 [94]

I think the answer would be 4/5

8 0
3 years ago
Solve using elimination -3x-4y=-1 and 3x-y=-4 *<br><br> (1,1)<br> (-1,1)<br> (1,-1)<br> (-1,-1)
galina1969 [7]
Using elimination (-1,1)
5 0
3 years ago
Read 2 more answers
F(x)=5-2x<br><br>PLEASE HELP DUE TODAY!!!
EastWind [94]
If f(1) =5-2(1)
F(2)=5-2(2)
3 0
3 years ago
2(x-3)=7x-31<br><br> 3x-2 (x+5)=-3+18<br><br> Please show your work
vredina [299]
2(x-3)=7x-31
2x-6=7x-31
-7x    -7x
----------------
-5x-6=-31
     +6   +6
--------------
-5x=-25
Divide by -5
x=5

3x-2(x+5)=-3+18
                     15
3x-2(x+5)=15
3x-2x-10=15
x-10=15               
 +10 +10
--------------
x=25
3 0
3 years ago
Find k so that the distance from (–1, 1) to (2, k) is 5 units. k= k= *there are two solutions for 2*
dalvyx [7]

Answer:

k = -3

k =5

Step-by-step explanation:

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d = 5\\(-1,1) =(x_1,y_1)\\(2,k)=(x_2,y_2)\\

5=\sqrt{\left(2-\left(-1\right)\right)^2+\left(k-1\right)^2}\\\\\mathrm{Square\:both\:sides}:\quad 25=k^2-2k+10\\25=k^2-2k+10\\\\\mathrm{Solve\:}\:25=k^2-2k+10:\\k^2-2k+10=25\\\\\mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\k^2-2k+10-25=25-25\\k^2-2k-15=0\\\\\mathrm{Solve\:by\:factoring}\\\\\mathrm{Factor\:}k^2-2k-15:\quad \left(k+3\right)\left(k-5\right)\\\mathrm{Solve\:}\:k+3=0:\quad k=-3\\

\mathrm{Solve\:}\:k-5=0:\quad k=5\\\\k =5 , k=-3

7 0
3 years ago
Read 2 more answers
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