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Leya [2.2K]
2 years ago
9

What is the hcf of 12 45 and 75​

Mathematics
1 answer:
Butoxors [25]2 years ago
4 0

Answer:

3

HCF of 12, 45 and 75 by Prime Factorization

As visible, 12, 45 and 75 have only one common prime factor i.e. 3. Hence, the HCF of 12, 45 and 75 is 3.

Step-by-step explanation:

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0.5, 0.04, 0.133, 0.021
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3) Sandy wants to make cookies. To make cookies, she needs 15 cups of flour per
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She can make 1.6 batches

Step-by-step explanation:

24/15 = 1.6

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WILL GIVE BRAINLIEST <br><br> 5 = h/3 - 17 <br> h = ?<br> (h/3 is a fraction)
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Answer:

h = 66

Step-by-step explanation:

We are given the equation of one variable h and we have to solve the equation for h.

The equation is given by 5 = \frac{h}{3} - 17

⇒ 5 + 17 = \frac{h}{3} {Adding 17 to both sides}

⇒ 22 = \frac{h}{3}

⇒ h = 22 × 3 {Since we know that if \frac{a}{b} = c then we can write a = bc}

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3 years ago
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The head of maintenance at XYZ Rent-A-Car believes that the mean number of miles between services is 3639 3639 miles, with a var
Andrei [34K]

Answer:

96.6% probability that the mean of a sample would differ from the population mean by less than 126 miles

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

A reminder is that the standard deviation is the square root of the variance.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question:

\mu = 3639, \sigma = \sqrt{145161} = 381, n = 41, s = \frac{381}{\sqrt{41}} = 59.5

Probability that the mean of the sample would differ from the population mean by less than 126 miles

This is the pvalue of Z when X = 3639 + 126 = 3765 subtracted by the pvalue of Z when X = 3639 - 126 = 3513. So

X = 3765

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3765 - 3639}{59.5}

Z = 2.12

Z = 2.12 has a pvalue of 0.983

X = 3513

Z = \frac{X - \mu}{s}

Z = \frac{3513 - 3639}{59.5}

Z = -2.12

Z = -2.12 has a pvalue of 0.017

0.983 - 0.017 = 0.966

96.6% probability that the mean of a sample would differ from the population mean by less than 126 miles

3 0
3 years ago
[50 pts] An even number, n, times the next consecutive number, n + 2, is equal to 168. Find the original number.
ale4655 [162]

<u>We are given:</u>

An even number 'n', multiplied by the next consecutive even number is 168

<u>Solving for n:</u>

From the given statement, we can say that:

n(n+2) = 168                      [<em>n multiplied by the next even number 'n+2'</em>]

n² + 2n = 168

n² + 2n - 168 = 0               [<em>subtracting 168 from both sides</em>]

We can see that we now have a quadratic equation, solving using splitting the middle term

n² + 14n - 12n - 168 = 0

n(n + 14) -12(n + 14) = 0      <em>[factoring out common terms</em>]

(n-12)(n+14) = 0

Here, we can divide both sides by either (n-12) OR (n+14)

Checking the result in both the cases:

(n + 14) = 0/(n-12)                     (n-12) = 0/(n+14)

n + 14 = 0                                 n - 12 = 0

n = -14                                      n = 12

Both these values are even and since we are not told if the number 'n' is positive or negative, both 12 and -14 are the possible values of n

4 0
2 years ago
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