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3 years ago

Morgan scored 42 points in 3 games. How many points would you expect him to make in an 11 game season?

Mathematics

2 answers:

Andreas93 [3]3 years ago

8 0

Answer:

154

Step-by-step explanation:

if the rate stays the same

HACTEHA [7]3 years ago

7 0

Answer:

see you have to set up a equation

Step-by-step explanation:

$3 = 11\\\\ 42 x 3x=462 3 3 =152$

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The n sequence question

MaRussiya [10]

Answer:

a) in order

-3;-2;-1

b) 6

1-4=-3

2-4=-2

3-4=-1

4-4=0

5-4=1

6-4=2

7-4=3

8-4=4

9-4=5

10-4=6

5 0

3 years ago

John, Sally, and Natalie would all like to save some money. John decides that it

brilliants [131]

Answer:

Part 1) John’s situation is modeled by a linear equation (see the explanation)

Part 2) $y=100x+300$

Part 3) $\$12,300$

Part 4) $\$2,700$

Part 5) Is a exponential growth function

Part 6) $A=6,000(1.07)^{t}$

Part 7) $\$11,802.91$

Part 8) $\$6,869.40$

Part 9) Is a exponential growth function

Part 10) $A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

Part 11) $\$13,591.41$

Part 12) $\$6,107.01$

Part 13) Natalie has the most money after 10 years

Part 14) Sally has the most money after 2 years

Step-by-step explanation:

Part 1) What type of equation models John’s situation?

Let

y ----> the total money saved in a jar

x ---> the time in months

The linear equation in slope intercept form

y=mx+b

The slope is equal to

$m=\$100\ per\ month$

The y-intercept or initial value is

$b=\$300$

$y=100x+300$

therefore

John’s situation is modeled by a linear equation

Part 2) Write the model equation for John’s situation

see part 1)

Part 3) How much money will John have after 10 years?

Remember that

1 year is equal to 12 months

$10\ years=10(12)=120 months$

For x=120 months

substitute in the linear equation

$y=100(120)+300=\$12,300$

Part 4) How much money will John have after 2 years?

Remember that

1 year is equal to 12 months

$2\ years=2(12)=24\ months$

For x=24 months

substitute in the linear equation

$y=100(24)+300=\$2,700$

Part 5) What type of exponential model is Sally’s situation?

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$P=\$6,000\\ r=7\%=0.07\\n=1$

substitute in the formula above

$A=6,000(1+\frac{0.07}{1})^{1*t}\\ A=6,000(1.07)^{t}$

therefore

Is a exponential growth function

Part 6) Write the model equation for Sally’s situation

see the Part 5)

Part 7) How much money will Sally have after 10 years?

For t=10 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{10}=\$11,802.91$

Part 8) How much money will Sally have after 2 years?

For t=2 years

substitute the value of t in the exponential growth function

$A=6,000(1.07)^{2}=\$6,869.40$

Part 9) What type of exponential model is Natalie’s situation?

we know that

The formula to calculate continuously compounded interest is equal to

$A=P(e)^{rt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

e is the mathematical constant number

we have

$P=\$5,000\\r=10\%=0.10$

substitute in the formula above

$A=5,000(e)^{0.10t}$

Applying property of exponents

$A=5,000(1.1052)^{t}$

therefore

Is a exponential growth function

Part 10) Write the model equation for Natalie’s situation

$A=5,000(e)^{0.10t}$ or $A=5,000(1.1052)^{t}$

see Part 9)

Part 11) How much money will Natalie have after 10 years?

For t=10 years

substitute

$A=5,000(e)^{0.10*10}=\$13,591.41$

Part 12) How much money will Natalie have after 2 years?

For t=2 years

substitute

$A=5,000(e)^{0.10*2}=\$6,107.01$

Part 13) Who will have the most money after 10 years?

Compare the final investment after 10 years of John, Sally, and Natalie

Natalie has the most money after 10 years

Part 14) Who will have the most money after 2 years?

Compare the final investment after 2 years of John, Sally, and Natalie

Sally has the most money after 2 years

3 0

3 years ago

A child plays a video game 155 times and wins the game 32 times. What is the experimental probability that the child loses the v

chubhunter [2.5K]

1 out of 5 games could be the answer

4 0

3 years ago

C. Identify the following as a constant, linear, or absolute value

bija089 [108]

Answer:

here is the answer bae. Feel free to ask for more

6 0

2 years ago

Read 2 more answers

How are the perimeters of the preimage polygon and the image polygon related? Explain.

Romashka-Z-Leto [24]

The difference between Pre-Image and Image is given as follows:

Image is the shape AFTER a transformation is the picture of the transformation.
A transformation's preimage is the shape BEFORE the change.

<h3>How do you define relationships between Image and Preimage?</h3>

Usually, the difference between image and pre-image is the way or method of transformation.

<h3>What is transformation in math?</h3>

A transformation is a broad phrase covering four distinct methods of changing the shape and/or location of a point, line, or geometric figure.

The Pre-Image is the original shape of the item, and the Image during the transformation is the final shape and location of the object.

The types of transformation in math are;

translation
rotation
reflection, and
dilation.

Learn more about pre-image:
brainly.com/question/8405245
#SPJ1

7 0

1 year ago