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Nostrana [21]
3 years ago
8

1.

Mathematics
2 answers:
nignag [31]3 years ago
6 0

Answer:

16 yellow flowers

Step-by-step explanation:

Pink: yellow\\6\:\::\:2\\\\Total\:ratio = 6+2 = 8\\\\48 \:pink\: flowers

First calculate total no of flowers

\frac{6}{8} \times x = 48\\\\\frac{6x}{8} =48\\\\Cross\:Multiply\\6x = 48\times 8\\6x = 384\\\\Divide\:both\:sides\:of\:the\:equation\:by\:6\\\frac{6x}{6} = \frac{384}{6} \\\\x = 64\\\\Total \:flowers = 64

Calculate no of yellow flowers

Total\:flowers-Pink\:flowers = Yellow\:flowers\\\\Yellow\:flowers = 64 - 48\\Yellow\:flowers =16

ira [324]3 years ago
4 0
The answer is 16 yellow flowers
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A group of students went on a field trip. The students were divided into 6 buses and each bus had less than 52 students. How man
Vikki [24]

Answer:

A maximum of 306

Step-by-step explanation:

You can estimate that since each bus had less than 52 students, that 51 were on each bus. 51 times 6=306

7 0
2 years ago
Read 2 more answers
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3241004551 [841]
Answer:

first option: Harulo is correct because the angle is coterminal with 3π / 4 and the reference angle is π / 4.

Explanation:

1) 19 π/4 = 4π + 3 π/4, which is 4 complete turns and 3/4 of turn.

2) 3 π/4 is in the third quadrant, so the reference angle is π - 3 π/4 = π/4

3) sin (π/4) = sin (3π/4) = (√2) / 2

4) csc (π/4) =  1 / [ sin (3π/4) ] = 1 / [ (√2) / 2 ] = 2 / (√2) = √2, which shows the validity of the statement and csc(19π/4) = √2.
3 0
3 years ago
A test is used to assess readiness for college. In a recent​ year, the mean test score was 20.3 and the standard deviation was 4
Vlada [557]

Answer:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low\leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

For this case we can consider a value to be significantly low if we have that the z  score is lower or equal to - 2 and we can consider a value to be significantly high if its z score is  higher tor equal to 2.

For this case we have the mean and the deviation given:

\mu = 20.3

\sigma = 4.9

And we can find the limits in order to consider values as significantly low and high like this:

Low \leq \mu -2 \sigma= 20.3- 2*4.9 = 10.5

High\geq \mu +2 \sigma= 20.3+ 2*4.9 = 30.1

6 0
3 years ago
The bearing from the Pine Knob fire tower to the Colt Station fire tower is N 65° E, and the two towers are 31 kilometers apart.
suter [353]

The distance are

a. 42.42

b. 15. 52

<h3>How to solve for the distance</h3>

80 = 65 + <ABC

<ABC = 80 - 65

= 15

Through the use of sine rule we would have

By using sine rule,

Sine 15/a = sine 135/b =

sin 30/30.

Next we have to solve b by cross multiplying

b = (30× sin135) / sin 30

= 21.21/0.5

b = 42.42 km

Also, the value of a will be:

= (42.42 × sin 15) / sin 135

= 10.98/0.7071

= 15.52

Read more on bearing here:

brainly.com/question/15221233

#SPJ1

3 0
1 year ago
Please help out I can’t really love this
77julia77 [94]
<h3>Answer:   Choice B)  45/56</h3>

========================================================

Explanation:

When we divide two fractions like this, we flip the second fraction and multiply like so...

\frac{5}{7} \div \frac{8}{9}\\\\\frac{5}{7} \times \frac{9}{8}\\\\\frac{5 \times 9}{7 \times 8}\\\\\frac{45}{56}\\\\

which points us to choice B as the answer.

The fraction 45/56 cannot be reduced further because 45 and 56 do not have any factors in common other than 1.

6 0
2 years ago
Read 2 more answers
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